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kenny6666 [7]
11 months ago
15

The terminal side of an < θ intersects the Unit Circle at point P=(5/6, -√11/6)

Mathematics
1 answer:
arlik [135]11 months ago
8 0

Given that the terminal side of an <θ intersects the unit circle at the point

P(\frac{5}{6},\frac{-\sqrt[]{11}}{6})

From the given point P:

\begin{gathered} x=\frac{5}{6} \\ y=\frac{-\sqrt[]{11}}{6} \\ \text{ s}ince,\text{ x is positive and y is negative, the angle lies in the 4th quadrant} \end{gathered}\begin{gathered} \tan \theta=\frac{\text{ opposite}}{\text{Adjacent}}=\frac{y}{x} \\ \tan \theta=\frac{\frac{-\sqrt[]{11}}{6}}{\frac{5}{6}}=\frac{-\sqrt[]{11}}{5} \\ \tan \theta=-0.6633 \\ \theta=326.44^0 \end{gathered}

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Half;  twice

Step-by-step explanation:

In a circle, the radius is said to be the distance from the center of the circle to any point on the edge of the circle, it is denoted as "r". The radius is called a radii if it is more than one.. The radius of a circle is half the length of the diameter of a circle because the diameter of a circle is the distance of the line that passes through the center of a circle touching both edges of the circle. It is denoted as "d".

Thus,

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For example, if the radius of a circle is 10cm, the diameter of the circle will be calculated as: d = 2 * 10 = 20cm. Which means if the radius is 10cm, diameter will be 20cm.

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