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ycow [4]
3 years ago
7

Norway, Sweden, and Finland (Scandinavia) have what kind of climates??

Physics
2 answers:
boyakko [2]3 years ago
8 0

Answer:

baltic + mild

Explanation:

Romashka [77]3 years ago
3 0
They have a mild climate. 
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The _________ ______ has the final say in both criminal and civil cases.
vagabundo [1.1K]
Judge/court has the final say
7 0
3 years ago
A particle starts from the origin at t = 0 with an initial velocity of 4.8 m/s along the positive x axis.If the acceleration is
tia_tia [17]

Answer:

Part a)

Velocity = 6.9 m/s

Part b)

Position = (3.6 m, 5.175 m)

Explanation:

Initial position of the particle is ORIGIN

also it initial speed is along +X direction given as

v_x = 4.8 m/s

now the acceleration is given as

\vec a = -3.2 \hat i + 4.6 \hat j

when particle reaches to its maximum x coordinate then its velocity in x direction will become zero

so we will have

v_f = v_i + at

0 = 4.8 - 3.2 t

t = 1.5 s

Part a)

the velocity of the particle at this moment in Y direction is given as

v_f_y = v_i + at

v_f_y = 0 + 4.6(1.5)

v_f_y = 6.9 m/s

Part b)

X coordinate of the particle at this time

x = v_x t + \frac{1}{2}a_x t^2

x = 4.8(1.5) - \frac{1}{2}(3.2)(1.5^2)

x = 3.6 m

Y coordinate of the particle at this time

y = v_y t + \frac{1}{2}a_y t^2

y = 0(1.5) + \frac{1}{2}(4.6)(1.5^2)

y = +5.175 m

so position is given as (3.6 m, 5.175 m)

5 0
3 years ago
A negatively charged plastic comb is brought close to, but does not touch, a small piece of paper. If the comb and the paper are
Irina-Kira [14]

If the comb and the paper are attracted to each other the charge on the paper, is D)must be positive

<h3>Laws of electrical attraction</h3>

This states that

  • Like charges attract
  • Unlike charges repel

Now, given that a negatively charged plastic comb is brought close to, but does not touch, a small piece of paper. If the comb and the paper are attracted to each other the charge on the paper, this implies that both the negatively charged plastic comb and the paper have opposite charges.

Since the charge on the plastic comb is negative, this means that the charge on the paper must be positive

So, if the comb and the paper are attracted to each other the charge on the paper, is D)must be positive

Learn more about electric charge here:

brainly.com/question/2373424

4 0
1 year ago
Two forces are acting on an object. The first force has magnitude F1=33.4 N and is pointing at an angle of θ1=23.8 clockwise fro
marishachu [46]

Answer:

Fe= 28.2 N : Magnitude of the equilibrant (Fe)

β = 18.34° , clockwise from the positive x axis

Explanation:

Concept of the equilibrant

It is called equilibrant  to a force with the same magnitude and direction as the resulting one (in case it is non-zero) but in the opposite direction. Adding vectorially to all the forces (that is to say the resulting one) with the equilibrant you get zero

To solve this problem we decompose the forces given into x-y components to find the resulting force:

Look at the attached graphic

F₁= 33.4 N  , θ₁=23.8° clockwise from the positive y axis (y+)

F₁x= 33.4 *sin23.8° = 13.48 N

F₁y= 33.4 *cos23.8° =30.6 N

F₂=46.1 N ,  θ₂=28.8 counterclockwise from the negative x axis (x-)

F₂x= -46.1 *cos28.8° = -40.4 N

F₂y=  -46.1 *sin28.8° =  -22.2 N

Components of the resultant in x-y R(x,y)

Rx= 13.48 N -40.4 N = - 26.92 N

Ry= 30.6 N  -22.2 N =  + 8.4 N

Components of the equilibrant in x-y Fe(x,y)

Fex= +26.92 N

Fey=  - 8.4 N

Magnitude of the equilibrant (Fe)

F_{e} = \sqrt{(F_{ex})^{2}+{(F_{ey})^{2}  }

F_{e} = \sqrt{(26.92)^{2}+(8.4)^{2}  }

Fe= 28.2 N

Angle the equilibrant makes with the x axis ( β)

\beta = tan^{-1} (\frac{F_{ey} }{F_{ex} } )

\beta = tan^{-1} (\frac-8.4 }{26.92 } )

β = -18.34°                  

β = 18.34° , clockwise from the positive x axis

8 0
2 years ago
Take the following measured gauge (or gage) pressures and convert them to absolute pressures in both kPa and psi units for an am
mamaluj [8]

Answer:

Explanation:

Given

ambient Pressure =98.10 kPa

(a)gauge pressure 152 kPa

we know

Absolute pressure=gauge pressure+Vacuum  Pressure

P_{abs}=152+98.10=250.1 kPa or 36.27 psi

(b)P_{gauge}=67.5 Torr or 8.99 kpa

as 1 Torr is 0.133 kPa

P_{abs}=8.99+98.10=107.09 kPa or 15.53 psi

(c)P_{vaccum}=0.1 bar or 10 kPa

Thus absolute pressure=98.10-10=88.10 kPa or 12.77 psi

as 1 kPa is equal to 0.145 psi

(d)P_{vaccum}=0.84 atm  or 85.113 kPa

as 1 atm is equal to 101.325 kPa

P_{abs}=98.10-85.11=12.99 kPa or 1.88 psi

6 0
2 years ago
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