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2 years ago

A 100 N force causes an object to accelerate at 2 m/s2. What is the mass of the object?

Physics

1 answer:

satela [25.4K]2 years ago

5 0

Answer:

50 kg

Explanation:

Given,

Force ( F ) = 100 N

Acceleration ( a ) = 2 m/s^2

To find : Mass ( m ) = ?

Formula : -

F = ma

m = F / a

= 100 / 2

m = 50 kg

Therefore, the mass of the object is 50 kg.

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A beam of protons moves in a circle of radius 0.20 m. The protons move perpendicular to a 0.36-T magnetic field. (a) What is the

gregori [183]

Answer:

a) $v=6.898\times 10^{6}\ m.s^{-1}$ is the speed of each proton

b) $F_c=3.97\times 10^{-13}\ N$

Explanation:

Given:

radius of path of motion, $r=0.2\ m$

we know charge on protons, $q=1.6\times 10^{-19}\ C$

magnetic field strength, $B=0.36\ T$

we've mass of proton, $m=1.67\times 10^{-27}\ kg$

From the equivalence of magnetic force and the centripetal force on the proton:

$F_B=F_C$

$q.v.B=\frac{m.v^2}{r}$

$q.B=\frac{m.v}{r}$

where:

v = speed of the proton

$(1.6\times 10^{-19})\times 0.36=\frac{1.67\times 10^{-27}\times v}{0.2}$

$v=6.898\times 10^{6}\ m.s^{-1}$ is the speed of each proton

Now the centripetal force on each proton:

$F_c=m.\frac{v^2}{r}$

$F_c=1.67\times 10^{-27}\times \frac{(6.898\times 10^6)^2}{0.2}$

$F_c=3.97\times 10^{-13}\ N$

6 0

3 years ago

While skiing in Jackson, Wyoming, your

grin007 [14]

Hello!

Work is equal to negative change in PE and PE=mgh and Power is change in work/change in time

So we have

56.1kg * 9.80m/s^2 * 16m = 8796.5 J of PE at top of run and -8796.5J of work done also

if it takes him 12s then we need to find the time gravity alone would bring him to the bottom. we get

16m=1/2at^2 and solving for t we get
t=sqrt(32/9.80m/s^2)=1.81s

so the difference in time is 12-1.8=11.2s

now we can find avg power=work/time = 8796.5J/11.2s = 785W or 785J/s

Hope this helps! Any questions please ask! Thank you!

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3 years ago

A satellite is in circular orbit at an altitude of 1500 km above the surface of a nonrotating planet with an orbital speed of 9.

Ksju [112]

To solve this problem we will use the Newtonian theory about the speed of a body in space for which the speed of a body in the orbit of a planet is summarized as:

$v = \sqrt{\frac{2GM}{R}}$