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poizon [28]
4 years ago
15

Mike is conducting an experiment in which he places several different types of soil in a funnel and then pours one liter of wate

r through each. He is careful to pack equal volumes of the soil samples tightly in the funnel and to make sure that only water makes it out of the bottom. He then records the amount of time it takes for half of the water to pass through the soil and out the bottom of the funnel. He records his data in the table below.
Soil Sample Time (seconds)
Soil W 181
Soil X 27
Soil Y 119
Soil Z 50

Which soil sample is the least permeable?
A.
Soil W
B.
Soil Z
C.
Soil Y
D.
Soil X
Physics
2 answers:
Agata [3.3K]4 years ago
4 0

Answer:

soil W

Explanation:

Permeability is a measure of how easily water flows through soil. A soil that is made up of large, jagged rocks is likely to be more permeable than a soil that is made up of compact clay.  One way to test a soil's permeability is to pour water through it. More permeable soil will allow water to pass through it rapidly, while less permeable soil will block more of the water.

quester [9]4 years ago
3 0

Permeability is a measure of how fast a liquid can pass through a layer of solid. In this case, the lesser the time, the more permeable the solid is. Or the other way around, the bigger the time, the less permeable the solid is. Therefore the answer in this problem is:

<span> A. Soil W</span>

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The resultant of two forces is 250 N and the same are inclined at 30° and 45° with resultant one on either side calculate the ma
Varvara68 [4.7K]

Answer:

The two forces are;

1) Force 1 with magnitude of approximately 183.013 N, acting 30° to the left of the resultant force

2) Force 2 with magnitude of approximately 129.41 N acting at an inclination of 45° to the right of the resultant force

Explanation:

The given parameters are;

The (magnitude) of the resultant of two forces = 250 N

The angle of inclination of the two forces to the resultant = 30° and 45°

Let, F₁ and F₂ represent the two forces, we have;

F₁ is inclined 30° to the left of the resultant force and F₂ is inclined 45° to the right of the resultant force

The components of F₁ are \underset{F_1}{\rightarrow} = -F₁ × sin(30°)·i + F₁ × cos(30°)·j

The components of F₂ are \underset{F_2}{\rightarrow} = F₂ × sin(45°)·i + F₂ × cos(45°)·j

The sum of the forces = F₂ × sin(45°)·i + F₂ × cos(45°)·j + (-F₁ × sin(30°)·i + F₁ × cos(30°)·j) = 250·j

The resultant force, R = 250·j, which is in the y-direction, therefore, the component of the two forces in the x-direction cancel out

We have;

F₂ × sin(45°)·i = F₁ × sin(30°)·i

F₂ ·√2/2 = F₁/2

∴ F₁ = F₂ ·√2

∴ F₂ × cos(45°)·j  + F₁ × cos(30°)·j = 250·j

Which gives;

F₂ × cos(45°)·j  + F₂ ·√2 × cos(30°)·j = 250·j

F₂ × ((cos(45°) + √2 × cos(30°))·j = 250·j

F₂ × ((√2)/2 × (1 + √3))·j = 250·j

F₂ × ((√2)/2 × (1 + √3))·j = 250·j

F₂ = 250·j/(((√2)/2 × (1 + √3))·j) ≈ 129.41 N

F₂ ≈ 129.41 N

F₁  = √2 × F₂ = √2 × 129.41 N ≈ 183.013 N

F₁  ≈ 183.013 N

The two forces are;

A force with magnitude of approximately 183.013 N is inclined 30° to the left of the resultant force and a force with magnitude of approximately 129.41 N is inclined 45° to the right of the resultant force.

5 0
3 years ago
In which item is energy stored in the form of gravitational potential energy? A. A slice of bread B. A compressed spring C. An a
marysya [2.9K]

The things that determine the amount of an object's gravitational potential energy are ...

-- mass of the object

-- gravitational acceleration in the place where the object is

-- height of the object above the ground or the floor

A). <em>a slice of bread; </em> No.  It's still a slice of bread even if it's on the ground.

B. <em>A compressed spring; </em> No.  It's still a compressed spring even if it's on the ground.

C. <em>An apple on a tree</em>; <em>Yes !</em>  It can't be an apple on a tree if it's on the ground.  

D. <em>A stretched bow string</em>; <em>No.</em>  It's still a stretched bowstring even if it's on the ground.

3 0
3 years ago
Read 2 more answers
A hockey player strikes a puck, giving it an initial velocity of 14.0 m/s in the positive x-direction. The puck slows uniformly
Advocard [28]

a) -1.71 m/s^2

b) 7.7 m/s

c) 4.39 s

Explanation:

a)

The acceleration of an object is the rate of change of velocity of an object.

In this problem, the acceleration of the puck can be found using the following suvat equation:

v^2-u^2=2as

where:

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance travelled

For the puck in this problem:

u = 14.0 m/s

v = 6.50 m/s

s = 45.0 m

So, the acceleration is:

a=\frac{v^2-u^2}{2s}=\frac{6.50^2-14.0^2}{2(45.0)}=-1.71 m/s^2

b)

The velocity of the puck at time t can be found by using another suvat equation:

v=u+at

where

u is the initial velocity

a is the acceleration

t is the time elapsed

v is the final velocity

Here, we have:

u = 14.0 m/s

a=-1.71 m/s^2 (found in part a)

Therefore, the velocity of the puck after t = 3.70 s is:

v=14.0+(-1.71)(3.70)=7.7 m/s

c)

Here we want to find the time taken for the puck to travel a distance of

s = 45.0 m

To solve this part, we can use again the suvat equation:

v=u+at

Where in this case, we use:

u = 14.0 m/s is the initial velocity

v = 6.50 m/s is the final velocity when the puck has travelled 45.0 m (this information is given in the question)

a=-1.71 m/s^2 is the acceleration (found in part a)

Therefore, by re-arranging the equation, we find the time taken to cover 45.0 m:

t=\frac{v-u}{a}=\frac{6.50-14.0}{-1.71}=4.39 s

7 0
3 years ago
What characteristics would an Earth-like planet need to have to support life?
kirza4 [7]

Answer:

water, air, vegetation, and light. also a good temperature thats not too hot or too cold

Explanation:

8 0
4 years ago
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Comets travel around the sun in elliptical orbits with large eccentricities. If a comet has speed 1.8×104 m/s when at a distance
natali 33 [55]

Answer:

9.4 x 10⁴ m/s

Explanation:

In circular or elliptical orbits , the angular momentum is conserved because torque is zero.  

mr₁v₁ = mr₂v₂

2.2 x 10¹¹ x 1.8 x 10⁴ = 4.2 x 10¹⁰ v₂

v₂ = 9.42 x 10⁴ m/s.

= 9.4 x 10⁴ m/s

7 0
3 years ago
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