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3 years ago

How can a scientist ensure that his or her data are reliable?

2 answers:

7 0

If the scientist repeats the experiment over and over and gets the same results. Also if the scientist peer reviews the experiment to make sure there is no bias in his or her results.

AleksAgata [21]3 years ago

6 0

Answer:

By repeating trials during an experiment

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Your car's 30.0 W headlight and 2.50 kW starter are ordinarily connected in parallel in a 12.0 V system. What power (in W) would

Tatiana [17]

Answer:

<h3>The power of headlight in series connection is 29.64 W</h3>

Explanation:

Given :

Power of headlight $P_{1} = 30$ W

Power of starter $P_{2} = 2500$ W

Voltage of headlight and starter $V = 12$ V

From equation of power,

$P = \frac{V^{2} }{R}$

$R = \frac{V^{2} }{P}$

For finding the resistance of headlight and starter,

⇒ For headlight,

$R_{1} = \frac{144}{30} = 4.8$ Ω

⇒ For starter,

$R_{2} = \frac{144}{2500} = 0.057$ Ω

Since equivalent resistance,

$R_{eq} = R_{1} + R_{2} + ........$

$R_{eq} = 4.8 +0.057 = 4.857$ Ω

So power in series is given by,

$P_{s } = \frac{V^{2} }{R_{eq} } = \frac{144}{4.857}$

$P_{s } = 29.64$ W

8 0

3 years ago

A Martian rover is descending a hill sloped at 30° with the horizontal. It travels with a constant velocity of 2 meters/second.

kodGreya [7K]

Vx = 2*cos30 = 1.73m's
Other words:
D = Vo*t = 1.4 * 21 = 31.5m. @ 30 Deg.
Dy = 31.5*sin30 = 15.75 m.

8 0

3 years ago

Read 2 more answers

A car was moving a 14 m/s. After 30 seconds, it’s speed increased to 20 m/s. What was its acceleration during this time?

Anuta_ua [19.1K]

Answer:

acceleration = 0.2 m/s/s

Explanation:

initial velocity u = 14

final velocity v = 20

time = 30

acceleration = ?

v = u + at

20 = 14 + 30a

30a = 6

a = 0.2 m/s/s

5 0

3 years ago

Read 2 more answers

A stuntwoman is going to attempt a jump across a canyon that is 77 m wide. The ramp on the far side of the canyon is 25 m lower

liq [111]

initial speed of the stuntman is given as

$v = 28 m/s$

angle of inclination is given as

$\theta = 15 degree$

now the components of the velocity is given as

$v_x = 28 cos15 = 27.04 m/s$

$v_y = 28 sin15 = 7.25 m/s$

here it is given that the ramp on the far side of the canyon is 25 m lower than the ramp from which she will leave.

So the displacement in vertical direction is given as

$\delta y = -25 m$

$\delta y = v_y * t + \frac{1}{2} at^2$

$-25 = 7.25 * t - \frac{1}{2}*9.8* t^2$

by solving above equation we have

$t = 3.12 s$

Now in the above interval of time the horizontal distance moved by it is given by

$d_x = v_x * t$

$d_x = 27.04 * 3.12 = 84.4 m$

since the canyon width is 77 m which is less than the horizontal distance covered by the stuntman so here we can say that stuntman will cross the canyon.

5 0

3 years ago

Joaquin mows the lawn at his grandmother’s home during the summer months. Joaquin measured the

nordsb [41]

Velocity is define as how fast an object is moving, and in what direction, it is a vector quantity, meaning velocity has both magnitude and direction. Anything goes to the left is negative, and anything goes to the right is positive.

a. Direction from east to west, given distance 11.5 meters, and time of 7.10 s

V = displacement/time V = -11.5/7.10 S V = -1.62 m/s (going left)

b. Joaquin reaches his original position. Displacement is now zero.

Velocity of the lawnmower is equal to "zero" but if we calculate for the average speed of the lawn, you just have to add the distance covered and the time it take to go back at the original position or point of origin

7 0

3 years ago