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qwelly [4]
3 years ago
9

A fixed amount of gas in a rigid container is heated from 300 k to 900 k, which of the following responses best describes what w

ill happen
a. increase in pressure by factor greater than3
b. pressure remains the same
c. pressure will decrease by a factor of 3
d. pressure increase by a factor of 3,
e. pressure increase by a factor less than 3
Chemistry
1 answer:
Llana [10]3 years ago
4 0

Answer: Option d. pressure increase by a factor of 3

Explanation:

P1 = P

T1 = 300k

T2 = 900K

P2 =?

Volume is constant.

P1/T1 = P2/T2

P/300 = P2/900

P2 x 300 = P x 900

P2 = (P x 900)/300

P2 = 3P

The pressure increased by a factor of 3

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The vapor pressure of ethanol is 1.00 × 102 mmHg at 34.90°C. What is its vapor pressure at 60.21°C? (ΔHvap for ethanol is 39.3 k
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Given the vapor pressure of ethanol at 34.90°C is 102 mmHg.

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We have given in the question

P_1=102\ mmHg

T_1=34.90\°\ C=34.90+273.15=308.05\ K\\T_2=60.21\°\ C=60.21+273.15=333.36\ K\\\Delta{vap}H=39.3 kJ/mol

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ln(\frac{P_2}{102})=\frac{39.3}{0.008314}(\frac{1}{308.05}-\frac{1}{333.36})\\\\ln(\frac{P_2}{102})=4726.967(\frac{333.36-308.05}{333.36\times308.05})\\\\ln(\frac{P_2}{102})=4726.967(\frac{25.31}{333.36\times308.05})\\\\ln(\frac{P_2}{102})=4726.967(\frac{25.31}{102691.548})\\\\ln(\frac{P_2}{102})=1.165

Taking inverse log both side we get,

\frac{P_2}{102}=e^{1.165}\\\\P_2=102\times 3.20\ mmHg\\P_2=327\ mmHg

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