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allochka39001 [22]
3 years ago
14

Jeremy saves $35 per month over the first 7 months of the year. He saves $40 per month over the next 5 months of the year. If Je

remy spends none of his savings, which expression shows how many dollars he will have saved by the end of the year?
Mathematics
2 answers:
cupoosta [38]3 years ago
8 0
(35x7)+(40x5)=445
Hope this helps :D
Firdavs [7]3 years ago
7 0

Answer: The expression shows the number of dollars he will have saved by the end of the year is given by 35(7)+40(5)=\$445

Step-by-step explanation:

Since we have given that

Amount he saved per month over the first 7 months = $35

Amount he saved per month over the next 5 months = $40

So, total saving by the end of the year is given by

35\times 7+40\times 5\\\\=\$245+\$200\\\\=\$445

Hence, the expression shows the number of dollars he will have saved by the end of the year is given by

35(7)+40(5)=\$445

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Step-by-step explanation:

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3 years ago
Suppose a subdivision on the southwest side of Denver, Colorado, contains 1,500 houses. The subdivision was built in 1983. A sam
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Answer:

0.0268 = 2.68% probability that the sample average is greater than $229,500

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Single house:

The mean appraised value of a house in this subdivision for all houses is $228,000, with a standard deviation of $8,500, which means that \mu = 228, \sigma = 8.5

Sample:

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This is 1 subtracted by the pvalue of Z when X = 229.5. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{229.5 - 228}{0.7759}

Z = 1.93

Z = 1.93 has a pvalue of 0.9732

1 - 0.9732 = 0.0268

0.0268 = 2.68% probability that the sample average is greater than $229,500

7 0
3 years ago
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denpristay [2]
The answer you're looking for is A: 3

5x-1=14
    +1  +1

(the -1 cancels out)

5x=15

(divide by 5 on both sides)

x=3

:P I hoped this helped!
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Answer:

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