A. Sodium is correct.
Sodium is an alkali metal.
Aluminum is a post-transitional metal- still a metal but it’s character is not as metallic as sodium.
Silicon is a metalloid- it has characteristics from both the metals and the non-metals.
Phosphorous is a non-metal.
The heat (Q) required to raise the temp of a substance is:<span>Q=m∗Cp∗ΔT</span><span> where m is the mass of the object (25.0g in this case), Cp is the specific heat capacity of the substance (for water Cp = 1.00cal/gC, or 4.18J/gC,
and Dt is the change in temp.
You'll have to solve this twice, once with the Cp in calories, and once with the Cp in joules.
</span><span>1380.72 Joules</span>
Answer:48kg of SiO2, 0.5kg of Al2O3, and 1.5kg of B2O3
Will be the final product
Explanation:
I) 96wt% of SiO2 will amount to 96/100*50 = 0.96*50=48kg of SiO2
ii) 1wt% of Al2O3 will amount to 1/100*50 = 0.01*50=0.5kg of Al2O3
III) 3wt% of B2O3 will amount to 3/100*50 = 0.03*50=1.5kg of B2O3..
The overall product form 48+ 0.5+1.5= 50kg
Answer:
2Na⁺ (aq) and 2OH⁻(aq)
Explanation:
Spectator ions:
Spectator ions are those ions which are same on both side of chemical reaction. These ions are same in the reactant side and product side. Their presence can not effect the chemical equilibrium that's why when we write the net ionic equation these ions are neglect or omitted.
Given ionic equation:
Ba⁺²(aq) + 2OH⁻(aq) + 2Na⁺ (aq) + CO²⁻₃(aq) → BaCO₃(s) + + 2Na⁺ (aq) + 2OH⁻(aq)
In given ionic equation by omitting the spectator ions i.e, 2Na⁺ (aq) and 2OH⁻(aq) net ionic equation can be written as,
Net ionic equation:
Ba⁺²(aq) + CO²⁻₃(aq) → BaCO₃(s)
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