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lions [1.4K]
3 years ago
14

How many molecules are in 3.8 grams of c6h6

Chemistry
2 answers:
kogti [31]3 years ago
7 0

Answer:

i dont really know how to explain but its the math

Explanation:

296.8249919999934

Vlada [557]3 years ago
7 0

Answer:

Molar mass of benzene [C6H6] = (12 × 6) + (6 × 1)

= 78 grams

from avogadro's number:

78 \: g \: of \: benzene = 6.02 \times  {10}^{23}  \: molecules \\ 3.8 \: g =  \{ \frac{3.8 \times (6.02 \times  {10}^{23}) }{78}  \} \\  \\  = { \boxed{ \boxed{2.93 \times  {10}^{22}  \: molecules}}}

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Given the following data: Fe2O3(s) + 3 CO(g) → 2 Fe(s) + 3 CO2(g) ΔH = −23 kJ 3 Fe2O3(s) + CO(g) → 2 Fe3O4(s) + CO2(g) ΔH = −39
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ΔH° = -11 kj

Explanation:

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To get this equation, we need to combine the 3 equations

We have to multiply the third equation by 2.

2Fe3O4(s) + 2CO(g) → 6 FeO(s) + 2CO2(g) ΔH = +54 kJ

<u>This equation we add to the second equation</u>

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3Fe2O3(s) + 3CO(g) →  3CO2(g) + 6FeO(s)

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<u>This new equation we will divide by 3 </u>

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Fe2O3(s) + CO(g) →  CO2(g) + 2FeO(s)

ΔH°  =-3/3 = -1 kJ

<u>Now we will substract this new equation from the first equation</u>

Fe2O3(s) + 3CO(g) - Fe2O3(s) - CO(g) → 2Fe(s) + 3CO2(g) -2FeO(s) - CO2(g)

2CO(g)  + 2FeO(s)  → 2Fe(s) + 2CO2(g)

ΔH° = -23kJ +1kJ

ΔH° = -22 kj

<u>The next equation we will divide by 2</u>

2CO(g)  + 2FeO(s)  → 2Fe(s) + 2CO2(g)

CO(g)  + FeO(s)  → Fe(s) + CO2(g)

ΔH° = -22kJ /2

ΔH° = -11 kj

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