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3 years ago

PLS HELP ASAP NO LINKS WILL MARK BRAINLIEST IF CORRECT

2 answers:

6 0

Answer:Strontium-90 and cesium-137 have half-lives of about 30 years (half the radioactivity will decay in 30 years). Plutonium-239 has a half-life of 24,000 years. High-level wastes are hazardous because they produce fatal radiation doses during short periods of direct exposure.

Explanation:

Alex777 [14]3 years ago

4 0

Answer:

10,000

Explanation:All toxic waste needs to be dealt with safely, not just radioactive waste. The radioactivity of nuclear waste naturally decays, and has a finite radiotoxic lifetime. Within a period of 10,000 years, the radioactivity of HLW decays to that of the originally mined ore. Its hazard then depends on how concentrated it is.

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Write the complete ionic equations, spectator ions and net ionic equation for the following.

gizmo_the_mogwai [7]

Answer:

Explanation:

1) ZnBr₂ (aq) + AgNO₃ (aq)

Chemical equation:

ZnBr₂ (aq) + AgNO₃ (aq) →Zn(NO₃)₂(aq) + AgBr(s)

Balanced chemical equation:

ZnBr₂ (aq) + 2AgNO₃ (aq) →Zn(NO₃)₂(aq) + 2AgBr(s)

Ionic equation:

Zn²⁺(aq) + Br₂²⁻ (aq) + 2Ag⁺ (aq)+ 2NO⁻₃ (aq) → Zn²⁺(aq) +(NO₃)₂²⁻(aq) + 2AgBr(s)

Net ionic equation:

Br₂²⁻ (aq) + 2Ag⁺ (aq) → 2AgBr(s)

The Zn²⁺((aq) and NO⁻₃ (aq) are spectator ions that's why these are not written in net ionic equation. The AgBr can not be splitted into ions because it is present in solid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.

2) HgCl₂ (aq) + KI (aq) →

Chemical equation:

HgCl₂ (aq) + KI (aq) → KCl + HgI₂

Balanced chemical equation:

HgCl₂ (aq) + 2KI (aq) → 2KCl(aq) + HgI₂(s)

Ionic equation:

Hg²⁺(aq) + Cl₂²⁻ (aq) + 2K⁺(aq) + 2I⁻ (aq) → HgI₂ (s) + 2K⁺(aq) + 2Cl⁻ (aq)

Net ionic equation:

Hg²⁺(aq) + 2I⁻ (aq) → HgI₂ (s)

The Cl⁻ ((aq) and K⁺ (aq) are spectator ions that's why these are not written in net ionic equation. The HgI₂ (s) can not be splitted into ions because it is present in solid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.

3) Ca(OH)₂ (aq) + Na₂SO₄ (aq)

Chemical equation:

Ca(OH)₂ (aq) + Na₂SO₄ (aq) → CaSO₄(s) + NaOH(aq)

Balanced chemical equation:

Ca(OH)₂ (aq) + Na₂SO₄ (aq) → CaSO₄(s) + 2NaOH(aq)

Ionic equation:

Ca²⁺(aq) + OH₂²⁻ (aq) + 2Na⁺(aq) + SO₄²⁻ (aq) → CaSO₄(s) + 2Na⁺(aq) + 2OH⁻ (aq)

Net ionic equation:

Ca²⁺(aq) + SO₄²⁻ (aq) → CaSO₄(s)

The OH⁻ ((aq) and Na⁺ (aq) are spectator ions that's why these are not written in net ionic equation. The CaSO₄ can not be splitted into ions because it is present in solid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.

4 0

3 years ago

At stp, a 12.0 liter sample of CH4 has the same total number of molecules as

Elden [556K]

Option 2: 12.0 L of $CO_{2} (g)$ at STP.

The standard pressure and temperature values are 1 atm and 273.15 K.

Using the ideal gas equation, number of moles of gas can be calculated which is as follows:

PV=nRT...... (1)

Here, P is pressure, V is volume, n is number of moles, R is gas constant and T is temperature.

Also, in 1 mole of any gas there are $6.023\times 10^{23}$ molecules of the gas. This is known as Avogadro's number and denoted by symbol $N_{A}$

Thus,

$N=n\times N_{A}$

Equation (1) can be rewritten as follows:

$PV=\frac{N}{N_{A}}RT$

On rearranging,

$N=\frac{P\times V\times N_{A}}{R\times T}$

Here, all the other terms are constant except volume, thus, gas with volume equal to the volume of $CH_{4}$ will have same number of molecules.

Volume of $CH_{4}$ gas and $CO_{2}$ gas is same thus, $CH_{4}$ will have same total number of molecules as $CO_{2}$ gas.

5 0

3 years ago

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Most of the sulfur used in the United States is chemically synthesized from hydrogen sulfide gas recovered from natural gas well

Harlamova29_29 [7]

Answer: Rate of production of Sulfur dioxide is 0.15kg/s to 2 significant digits

Note: The question is incomplete. The complete question is as follows:

Most of the used in the United States is chemically synthesized from hydrogen sulfide gas recovered from natural gas wells. In the first step of this synthesis, called the Claus process, hydrogen sulfide gas is reacted with dioxygen gas to produce gaseous sulfur dioxide and water Suppose a chemical engineer studying a new catalyst for the Claus reaction finds that 198. liters per second of dioxygen are consumed when the reaction is run at 186. °C and 0.69 atm. Calculate the rate at which sulfur dioxide is being produced. Give your answer in kilograms per second. Round your answer to 2 significant digits.

Explanation:

The balanced equation of the reaction between hydrogen sulfide gas and dioxygen gas to produce sulfur dioxide and water is as follows:

2H₂S(g) + 3O₂(g) ---> 2SO₂(g) + 2H₂O(g)

From the equation above, 3 moles of dioxide yields 2 moles of sulfur dioxide.

Using the ideal gas equation to determine the number of moles of dioxygen present in 198 litres of the gas at 186. °C and 0.69 atm;

PV = nRT,

where P = 0.69atm, V = 198Litres, R (molar gas constant) = 0.082atmLK⁻¹mol⁻¹, T = 186. °C = 459K

n = PV/RT

n = 0.69*198*/(0.082*459)

n = 3.63moles of dioxygen

Therefore, 3.63 moles of dioxygen are consumed per second

Using the mole ratio from the equation of reaction,

number of moles of sulfur dioxide produced will be 3.63moles * 2/3 = 2.42moles

Therefore, the number of moles of sulfur dioxide consumed is 2.42 moles per second.

Converting to kilograms per second,

1 mole of sulfur dioxide weighs 64g (molar mass of sulfur dioxide)

2.42 moles weighs 2.42*64g =154.88g or 0.15488Kg which is approximately 0.15Kg

Therefore, rate of production of Sulfur dioxide is 0.15kg/s to 2 significant digits

8 0

3 years ago

Auroras are lights that appear at Earth’s northern and southern poles. What is the main cause of an aurora?

rusak2 [61]

A full understanding of the physical processes which lead to different types of auroras is still incomplete, but the basic cause involves the interaction of the solar wind with the Earth’s magnetosphere. The varying intensity of the solar wind produces effects of different magnitudes, but includes one or more of the following physical scenarios. so the answer is A

4 0

3 years ago

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Is freezing depression dependent on having a salt solute, or can non-ionic particles also have an affect on the freezing point o

luda_lava [24]

Answer:

It is not dependent on the salt solute at all but the solute does have an affect.

Explanation:

in the equation you maybe aware of the I factor which represents the ions present in the solution. a non ionic will always have a I value of 1 a ionic can be 2 like in NaCl. What this means that all non ionic will lower the temperature depression but ionics will have a greater affect because for example salt breaks into Na and Cl will essentially hae more impurities than glucose which doesnt dissociate and will have a I value of 1

5 0

3 years ago