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3 years ago

PLS HELP ASAP NO LINKS WILL MARK BRAINLIEST IF CORRECT

2 answers:

6 0

Answer:Strontium-90 and cesium-137 have half-lives of about 30 years (half the radioactivity will decay in 30 years). Plutonium-239 has a half-life of 24,000 years. High-level wastes are hazardous because they produce fatal radiation doses during short periods of direct exposure.

Explanation:

Alex777 [14]3 years ago

4 0

Answer:

10,000

Explanation:All toxic waste needs to be dealt with safely, not just radioactive waste. The radioactivity of nuclear waste naturally decays, and has a finite radiotoxic lifetime. Within a period of 10,000 years, the radioactivity of HLW decays to that of the originally mined ore. Its hazard then depends on how concentrated it is.

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Calculate the amount of heat energy required to convert 55.0 g of water at 62.5°C to steam at 124.0°C. (Cwater = 4.18 J/g°C; Cst

Grace [21]

Answer:

= 135,647.65 Joules or 135.65 kJ

Explanation:

Heat require to raise the temperature of 55 g water from 62.5°C to 124.0°C will be calculated in steps;

Step 1; heat required to raise water from 62.5°C to 100 °C

Heat = 55 g × 4.18 J/g°C × (100 -62.5)

= 8,621.25 Joules

Step 2; Heat required to convert water to steam without change in temperature;

Heat = moles × Molar Latent heat of vaporization.

= (55g / 18 g/mol)× 4.07 ✕ 104 J/mol

= 12.436 × 10^4 Joules

Step 3: Heat required to raise the temperature of steam from 100°C to 124 °C.

Heat = mass × specific heat capacity × ΔT

= 55 g × 2.02 J/g°C × (124-100)

= 2,666.4 Joules

Therefore; total amount of heat required is;

= 8,621.25 J + 124360 J + 2,666.4 J

<u> = 135,647.65 Joules or 135.65 kJ</u>

4 0

3 years ago

What is the oxidation number of Cl in chlorate ion ClO3?

Kryger [21]

The correct answer to this question is "5." the oxidation number of cl in ClO3 will be a positive 5 because oxygen is naturally a -2 charge. times that by three and then account for the negative charge of the CLO3- ion.

8 0

3 years ago

Read 2 more answers

Match the following terms with their definitions:

stepan [7]

Hi,

Homogeneous mixture 2
Heterogeneous 3
Mixture 1
Solution 5
Compound 4

6 0

3 years ago

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3. A 31.2-g piece of silver (s = 0.237 J/(g · °C)), initially at 277.2°C, is added to 185.8 g of a liquid, initially at 24.4°C,

VARVARA [1.3K]

Answer:

$Cp_{liquid}=2.54\frac{J}{g\°C}$

Explanation:

Hello,

In this case, since silver is initially hot as it cools down, the heat it loses is gained by the liquid, which can be thermodynamically represented by:

$Q_{Ag}=-Q_{liquid}$

That in terms of the heat capacities, masses and temperature changes turns out:

$m_{Ag}Cp_{Ag}(T_2-T_{Ag})=-m_{liquid}Cp_{liquid}(T_2-T_{liquid})$

Since no phase change is happening. Thus, solving for the heat capacity of the liquid we obtain:

$Cp_{liquid}=\frac{m_{Ag}Cp_{Ag}(T_2-T_{Ag})}{-m_{liquid}(T_2-T_{liquid})} \\\\Cp_{liquid}=\frac{31.2g*0.237\frac{J}{g\°C}*(28.3-227.2)\°C}{185.8g*(28.3-24.4)\°C}\\ \\Cp_{liquid}=2.54\frac{J}{g\°C}$

Best regards.

6 0

3 years ago

Because water molecules are polar and carbon dioxide molecules are nonpolar,

Gala2k [10]

The correct is D.

Water is a polar molecule and it has polar bonds, which carry partially positive and partially negative charges. This polar bond increases the attraction between molecules of water and thus it requires a greater energy to break the bond between the molecules of water compare to carbon dioxide, which is a non polar molecule. Thus, water has a higher boiling point than carbon dioxide.

4 0

3 years ago

Read 2 more answers