Answer:
Radiation
Conduction
Convection
Explanation:
<u>Radiation:</u> Transfer of heat by electromagnetic rays (Example: A microwave heating food)
<u>Conduction:</u> Transfer of heat energy from one object to another through direct contact (Example: Getting out of bed and your warm feet touch cold tile, making the tile warm and your feet cold)
<u>Convection:</u> Movement of heat by a fluid such as air or water (Example: A convectional oven works by heating the air inside the oven to evenly cook food)
Hope this helps!
Answer:
Heat of vaporization: 250.580 kJ/mol. Number of Protons/Electrons: 47. Number of neutrons: 61. Classification: Transition Metal.
Explanation:
The principle states that the lowest-energy orbitals are filled first, followed ... electron configuration The arrangement of electrons in an atom, molecule, or other ... and two valence electrons (electrons in the outer shell), respectively; because of this, ... mechanics, a certain energy is associated with each electron configuration.
Answer:

Explanation:
We have the reactions:
A: 
B: 
Our <u>target reaction</u> is:

We have
as a reactive in the target reaction and
is present in A reaction but in the products side. So we have to<u> flip reaction A</u>.
A: 
Then if we add reactions A and B we can obtain the target reaction, so:
A: 
B: 
For the <u>final Kc value</u>, we have to keep in mind that when we have to <u>add chemical reactions</u> the total Kc value would be the <u>multiplication</u> of the Kc values in the previous reactions.


Answer:It would never stop until something hit the ball, to slow it down.
Explanation:
This is so because there is no gravitational pull in space.