The domain of f/g
consists of numbers x for which g(x) cannot equal 0 that are in the domains of
both f and g.
Let’s take this equation as an example:
If f(x) = 3x - 5 and g(x)
= square root of x-5, what is the domain of (f/g)x.
For x to be in the domain of (f/g)(x), it must be
in the domain of f and in the domain of g since (f/g)(x) = f(x)/g(x). We also
need to ensure that g(x) is not zero since f(x) is divided by g(x). Therefore,
there are 3 conditions.
x must be in the domain of f:
f(x) = 3x -5 are in the domain of x and all real numbers x.
x must be in the domain of g:
g(x) = √(x - 5) so x - 5 ≥ 0 so x ≥ 5.
g(x) can not be 0: g(x)
= √(x - 5) and √(x - 5) = 0 gives x = 5 so x ≠ 5.
Hence to x x ≥ 5 and x ≠ 5
so the domain of (f/g)(x) is all x satisfying x > 5.
Thus, satisfying <span>satisfy all
three conditions, x x ≥ 5 and x ≠ 5 so the domain of (f/g)(x) is all x
satisfying x > 5.</span>
Answer:
21 cents
Step-by-step explanation:
X^2 - 8x - 6x + 48 i think
Hello!
Acute angles are angles less than 90°
A right angle is a angle that is exactly 90°
A Obtuse angle is a angle that is more than 90°
Looking at the picture there are
acute angles - 2
obtuse angles - 2
right angles - 0
Hope this helps!
Answer:
v = 18π
Step-by-step explanation:
v = πr²h
plug in the givens
v = π(3²)2
v = 18π exact answer
V = 18 * 3.14 = 56.52 decimal approximation
