Option A is correct.
For testing, if x is a significant predictor of y in simple linear regression, we need to determine if the <u>slope </u><u>is </u><u>significantly different </u><u>from</u><u> zero</u>.
What is linear regression?
A statistical technique known as linear regression is used to represent the connection between a scalar answer and one or more explanatory factors. When there is just one explanatory variable, simple linear regression is employed; when there are numerous explanatory variables, multiple linear regression is utilized.
Based on the value of another variable, linear regression analysis makes predictions about the value of the first variable. The dependent variable is the one you're trying to forecast. The independent variable is the one you are utilizing to make a prediction about the value of the other variable.
Find more on linear regression: brainly.com/question/25987747
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Answer:
=1.99 sec
Step-by-step explanation:
t=k√d
k= constant
3=k√34.1
3=5.839k
k=0.5137
t=0.5137√15
t=1.99 sec
Answer: x=7 and AC = 44 unuts.
Step-by-step explanation:
We know that the diagonals of a parallelogram bisect each other. (i)
Here in parallelogram ABCD , AC and Bd are diagonals intersecting at E.
BE = 2x + 2, BD = 5x – 3, and AE = 4x – 6
Using (i)
Now , AE = 4(7)-6 = 28-6 = 22
AC =2 AE = 2 (22) =44 units.
Hence, x=7 and AC = 44 unuts.
Answer:
I think the answer is 44.13
Step-by-step explanation:
sorry if I am wrong
Answer:
a) 0.6032
b)
Lower limit: 0.48
Upper limit: 0.72
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
Question a:
In a random sample of 63 professional actors, it was found that 38 were extroverts.
We use this to find the sample proportion, which is the point estimate for p. So
Question b:
Sample of 63 means that 
95% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
The lower limit of this interval is:
The upper limit of this interval is:
Rounding to two decimal places:
Lower limit: 0.48
Upper limit: 0.72
