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devlian [24]
1 year ago
10

If the statement is e is the midpoint of df what is the reason

Mathematics
1 answer:
Katena32 [7]1 year ago
3 0

For E to be the midpoint of DF, it needs to divide DF in 2 equal segments, DE and EF. If E is the midpoint of DF, then DE and EF are equal, so the reason is that the expressions for DE and EF are equal. The reason is:

6x+5=8x-1

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A circle passes through point (-2, -1) and its center is at (2, -1). Which equation represents the circle?
Anastaziya [24]

Answer:

  \text{A)}\qquad (x-2)^2+(y+1)^2=16

Step-by-step explanation:

The formula for a circle of radius r centered at (h, k) is ...

  (x -h)^2 +(y -k)^2 = r^2

Both of the given points are on the line y=-1. The distance between them is the difference of their x-coordinates, 2 -(-2) = 4. So, the radius of the circle is 4 and the equation becomes ...

  (x -2)^2 +(y -(-1))^2 = 4^2

  (x -2)^2 +(y +1)^2 = 16 . . . . . . . . . matches choice A

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Which is the graph of y =(x) - 2?
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Answer: i dont see the graphs

Step-by-step explanation:

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What is a linear equation of a line with slope -4 and y-intercept 7
ololo11 [35]

The equation would look like

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5 0
3 years ago
Suppose a baker claims that the average bread height is more than 15cm. Several of this customers do not believe him. To persuad
laila [671]

Answer:

17-2.262\frac{1.9}{\sqrt{10}}=15.641    

17+2.262\frac{1.9}{\sqrt{10}}=18.359    

So on this case the 95% confidence interval would be given by (15.641;18.359)    

And since the lower limit for the confidence interval is higher than 15 we can conclude that at 5% of significance the true mean is higher than 15 cm

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=17 represent the sample mean

\mu population mean (variable of interest)

s=1.9 represent the sample standard deviation

n=10 represent the sample size  

Confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=10-1=9

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,9)".And we see that t_{\alpha/2}=2.262

Now we have everything in order to replace into formula (1):

17-2.262\frac{1.9}{\sqrt{10}}=15.641    

17+2.262\frac{1.9}{\sqrt{10}}=18.359    

So on this case the 95% confidence interval would be given by (15.641;18.359)    

And since the lower limit for the confidence interval is higher than 15 we can conclude that at 5% of significance the true mean is higher than 15 cm

4 0
3 years ago
What is the length of a diagonal of a rectangular picture whose sides are 12 inches by 17 inches? Round to the nearest tenth of
Nostrana [21]

Answer: d≈20.81in

Hope this helpsss!!!

6 0
3 years ago
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