Question

below is a list of some weak acids: name formula pka molar mass acetic acid h(c2h3o2) 4.76 60.052 butanoic acid h(c4h7o2) 4.83 88.104 formic acid h(cho2) 3.75 46.026 heptanoic acid h(c7h13o2) 4.89 130.182 hexanoic acid h(c6h11o2) 4.84 116.16 hydrocyanic acid hcn 9.21 27.028 hydrofluoric acid hf 3.2 20.008 lactic acid h(c3h5o3) 3.08 90.078 nitrous acid hno2 3.25 47.018 octanoic acid h(c8h15o2) 4.89 144.208 pentanoic acid h(c5h9o2) 4.84 102.13 propanoic acid h(c3h5o2) 4.86 74.078 uric acid h(c5h3n4o3) 3.89 168.122 below is a graph of the titration of a 0.269 g of a weak acid from the table with 0.09560 m naoh solution. what is the volume of naoh used to reach the equivalence point? 24 ml what is the volume of naoh used to reach the 50% t (half-way equivalence point)? number units what is the pka of the unknown acid? number what is the molecular weight of the unknown acid? number units what is the unknown acid?

Answer 1

(i) Volume of point Naon to reach equivalence. = 24.0mL

(ii) volume of Naon used to reach 50% T = 12.0mL

(iii) PKA of an unknown acid = 4.8

(iv) moles of acid reacted = moles of NaOH

man/molar mass = 0.269g/MW = Molarity x volume

0.269g/MW =  0.09560 mol/K x 24. 0×$10^{-3}$/K

MW = 0.269g/0.09560 mol x 24.0x$10^{-3}$

MW = 117.24g mol-1

(v) In matching the given table of molar masses. with obtained man matches with that, we get that it of hexanoic acid.

unknown acid = hexanoic acid

Titration is used to determine the amount of a substance present by reacting it with a known amount of another substance. For example, the molar mass of an acid can be found by titrating it with a base solution of known concentration. Your unknown solid is an acid. This is dissolved in water and phenolphthalein indicator is added and titrated to the endpoint with standard NaOH solution. Unknown acids are monobasic. There is only one acidic hydrogen per molecule.

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