Answer:
E) Intramolecular bond angles change
Explanation:
Infrared Radiation:
IR is electromagnetic radiations. The wavelength i.e. 700nm to 1000 mm of infrared is longer than invisible light and Its frequency is lower than light, that's why it is invisible to light.
- When IR radiation strike the molecule it absorbed by this molecule.
- This radiation used to identify and study chemicals.
- Infrared radiation interact with intra-bonds of the molecule.
- Bonds in the molecules have vibrational translational and rotational movements
- Due to these vibration, rotation and translation movement it absorb a radiation of specific frequency and wavelength
- These movements of bond are very small and absorbs radiations of very low frequency
- So when Infrared light or radiation absorbed the intra-bonds of the molecule get affected and angles of these bonds changes.
- As the frequency of the absorbed radiation matches the frequency of the bond that vibrates.
So
The correct option is option E
E) Intramolecular bond angles change
* Note:
it couldn't be option A as the frequency of IR is not enough to rotate a whole molecule
It Couldn't be option B as IR rations are electromagnetic radiation of longer wave length so it one can not see it with light so how it will glow a molecule
It also not could be the option C as for the excitation of electrons require much higher energy.
It also not the option D as nuclear magnetic spin is associated with nuclear magnetic radiation that are much different from IR.
Answer:
Explanation:
Work function of potassium = 2.29 eV = 3.67 X 10⁻¹⁹ J
So the minimum energy of photon must be equal to 3.67 X 10⁻¹⁹ J .
energy of photon of wavelength λ = hc / λ
where h = 6.67 x 10⁻³⁴
c = 3 x 10⁸
Putting the values in the equation above
6.67 x 10⁻³⁴ x 3 x 10⁸ / λ = 3.67 X 10⁻¹⁹
λ = 6.67 x 10⁻³⁴ x 3 x 10⁸ / 3.67 X 10⁻¹⁹
= 5.452 x 10⁻⁷
= 5452 x 10⁻¹⁰ m
= 5452 A .
Answer:
[OH-] = 6.17 *10^-10
Explanation:
Step 1: Data given
pOH = 9.21
Step 2: Calculate [OH-]
pOH = -log [OH-] = 9.21
[OH-] = 10^-9.21
[OH-] = 6.17 *10^-10
Step 3: Check if it's correct
pOH + pH = 14
[H+]*[OH-] = 10^-14
pH = 14 - 9.21 = 4.79
[H+] = 10^-4.79
[H+] = 1.62 *10^-5
6.17 * 10^-10 * 1.62 * 10^-5 = 1* 10^-14
Answer: <u>Four</u>Explanation: Calcium Sulfide is an ionic compound made up of Ca²⁺ and S²⁻.
Ca²⁺ is formed as,
Ca → Ca²⁺ + 2 e⁻
These two electrons are accepte by Sulfur as,
S + 2 e⁻ → S²⁻
So, before accepting 2 electrons S was having six valence electrons, after accepting two electrons from Ca it has 8 electrons which are present in four pairs as shown below,
Answer: is letter D. Because minerals are solid.
Explanation:
