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Lelu [443]
11 months ago
14

Which element in Group 17 is the most active nonmetal? (1) Br (2) I (3) Cl (4) F

Chemistry
1 answer:
Maksim231197 [3]11 months ago
7 0

The element of the group 17 that is most active non metal is fluorine.

The group 17 of the periodic table contains bromine(Br), iodine(I), Chlorine(Cl) and fluorine(F).

Among all the elements of the group 17. Fluorine is the smallest in size.

Because of the small size of fluorine it has the highest electronegativity in group 17.

This high electronegativity makes it a very active non metal. It provides a very high oxidizing power and low dissociation energy to the fluorine atom.

Also because of the very small size the source of attraction between the nucleus and the electrons is very high in floor in atom.

It reacts readily to form oxides and hydroxides.

So, we can conclude here that fluorine is the most active non metal of group 17.

To know more about group 17, visit,

brainly.com/question/26440054

#SPJ4

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The ancient Egyptians used black eye make up with which element just give me an element don’t give me a definition
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Answer:

galena

Explanation:

The green eye paint was made of malachite, a copper carbonate pigment, and the black kohl was made from galena, a dark grey ore.

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Why is the volume of hydrogen is doubled the volume of oxygen in electrolysis of water?​
maria [59]

Explanation:

As you can that water splits into molecules of hydrogen and 1 molecules of oxygen since , number of molecules of hydrogen released is double the number of molecules of oxygen released, volume occupied by hydrogen gas is double the volume occupied by oxygen gas

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Compare the properties of elements in groups 17 and group 18. Make sure to cover the following points:
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The answer for this question is b
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2 years ago
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What is an ion atom?
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3 years ago
The reaction (CH3)3CBr + OH- (CH3)3COH + Br- in a certain solvent is first order with respect to (CH3)3CBr and zero order with r
son4ous [18]

Answer and Explanation:

The rate constant (K) is related to activation energy (Ea), frequency factor (A) and temperature (T) in Kelvin by the equation

R = molar gas constant

K = A(e^(-Ea/RT))

Taking natural log of both sides

In K = In A - (Ea/RT)

In K = (-Ea/R)(1/T) + In A

Comparing this to the equation of a straight line; y = mx + c

y = In K, slope, m = (-Ea/R), x = (1/T) and intercept, c = In A

a) From the question, m = (-Ea/R) = -1.10 × (10^4) K

(-Ea/R) = -1.10 × (10^4) = -11000

R = 8.314 J/K.mol

Ea = -11000 × 8.314 = 91454 J/mol = 91.454 KJ/mol

b) c = In A = 33.5

A = e^33.5 = (3.54 × (10^14))/s

c) K = A(e^(-Ea/RT))

A = (3.54 × (10^14))/s, Ea = 91454 J/mol, T = 25°C = 298.15 K, R = 8.314 J/K.mol

K = (3.54 × (10^14))(e^(-91454/(8.314×298.15))) = 0.0336/s

QED!

5 0
3 years ago
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