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taurus [48]
3 years ago
15

PLEASE HELP ME! Determine the number of atoms in 4.27 g gold.

Chemistry
1 answer:
solmaris [256]3 years ago
6 0

This can be done with some simple dimensional analysis. First you convert your gram of gold into moles of gold There are 196.97 grams of gold for every one mole of gold so you divide 4.27 by 196.67 to get 0.0217 moles of gold. You then multiply the moles of gold by Avogadro's number, 6.02 X 10^23. Avogadro's number indicates the number of atoms in one mole. Therefore, there are 1.307 X 10^22 atoms in 4.27 grams of gold.  

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4 0
3 years ago
Read 2 more answers
The antibiotic doxycycline is used to treat Lyme disease. A 100 mg dose of the antibiotic consists of 59.5 mg of C, 5.40 mg of H
never [62]

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In order to determine the empirical formula of doxycycline, we need to follow a series of steps.

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H: 5.40 mg/100 mg × 100% = 5.40%

N: 6.30 mg/100 mg × 100% = 6.30%

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Step 2: Divide each percentage by the atomic mass of the element

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Step 3: Divide all the numbers by the smallest one

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N: 0.450/0.450 = 1

O: 1.80/0.450 = 4

The empirical formula of doxycycline is C₁₁H₁₂NO₄

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3 years ago
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