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Stels [109]
1 year ago
6

Can the element gold kick out magnesium from a compound?

Chemistry
1 answer:
Misha Larkins [42]1 year ago
7 0

Gold cannot replace Magnesium from a compound as gold is placed lowest in the reactivity series of metals. It won't even react with the compound let alone replace it. Gold has great ductile strength and malleability.

 Features of Reactivity Series of Metals

  • The metals at the top of the reactivity series are powerful reducing agents since they are very easily oxidized. These metals tarnish or corrode very easily though.
  • The reducing ability of the metals grows weaker while traversing down the reactivity series.
  • The electro-positivity of the elements also reduces while moving down the reactivity series of metals.
  • All metals that are found above hydrogen in the activity series liberate H2 gas upon reacting with dilute hydrochloric acid(HCl) or dilute sulphuric acid(H2SO4).
  • Metals than on the reactivity series have the ability to displace metals that are placed lower from their salt solutions such as Mg can replace Au but Au cannot replace Mg as Au is kept lowest in the reactivity series
  • Higher ranking metals require greater energy for their isolation from ores and other compounds to stay highly reactive.

Therefore Gold cannot replace Magnesium from a compound as it is the least reactive metal and therefore, comes lower than Magnesium in the reactivity series

Learn about reactivity series

brainly.com/question/15304384

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When the temperature of a sample of neon gas increases, what else increases? Distance between the atoms Kinetic energy of the at
Allushta [10]

Answer: Kinetic Energy of the atoms also increases.

Explanation: We are given that the temperature of the gas increases.

Relation between kinetic energy and temperature follows:

K.E._({avg})=\frac{3RT}{2N_A}

where, K = Average Kinetic energy

R = Gas constant

T = Temperature

N_A = Avogadro's number

As seen from the relation above, the Kinetic energy of the gas is directly proportional to the temperature, hence as the temperature increases, kinetic energy of the atom also increases.

4 0
3 years ago
Rewrite and Balance the Equation <br> N₂ + H₂ -&gt; NH3
Mars2501 [29]

Answer:N

2

+ 3

H

2

-----> 2N

H

3

Explanation:

N

2

+

H

2

-----> N

H

3

Let us balance this equation by counting the number of atoms on both sides of the arrow.

N

2

+

H

2

-----> N

H

3

N=2 , H=2 N=1, H=3

To balance the number of N atom on Right Hand Side (RHS) , I will add one molecule of N

H

3

on RHS

N

2

+

H

2

-----> 2N

H

3

N=2 , H=2 N=2 , H= 6

To balance the number of H atoms on Left Hand Side (LHS) , I will add two molecules of

H

2

on LHS

N

2

+ 3

H

2

-----> 2N

H

3

N=2 , H=6 N=2 , H= 6

Answer link

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4 0
3 years ago
Read 2 more answers
How many moles are present in a 5.8 g sample of copper?
Oksanka [162]

Explanation:

Molar mass of Cu = 63.5g/mol

Moles of Cu

= 5.8g / (63.5g/mol) = 0.091mol (B)

8 0
2 years ago
Does anyone know how to do this?
o-na [289]

Answer:

nop sorry

Explanation:

3 0
2 years ago
1.33 dm3 of water at 70°C are saturated by 2.25
astraxan [27]

Given that 4.50 dm³ of Pb(NO₃)₂ is cooled from 70 °C to 18 °C, the

amount amount of solute that will be deposited is 1,927.413 grams.

<h3>How can the amount of solute deposited be found?</h3>

The volume of water 1.33 dm³ of water 70 °C.

The number of moles of Pb(NO₃)₂ that saturates 1.33 dm³ of water at 70 °C  = 2.25 moles

At 18 °C, the number of moles of Pb(NO₃)₂ that saturates 1.33 dm³ of water = 0.53 moles

Therefore;

Number of moles of Pb(NO₃)₂ in 4.50 dm³ at 70 °C is therefore;

1.33 dm³ contains 2.25 moles.

Number \ of \ moles \ in \ 4.50 \ dm^3 = \dfrac{2.25}{1.33} \times 4.50 \approx \mathbf{7.613 \, moles}

Number of moles of Pb(NO₃)₂ in 4.50 dm³ at 70 °C ≈ 7.613 moles

Number of moles of Pb(NO₃)₂ in 4.50 dm³ at 18 °C is therefore;

1.33 dm³ contains 0.53 moles

Number \ of \ moles \ in \ 4.50 \ dm^3 = \dfrac{0.53}{1.33} \times 4.50 \approx \mathbf{1.79 \, moles}

Number of moles of Pb(NO₃)₂ in 4.50 dm³ at 18 °C ≈ 1.79 moles

The number of moles that precipitate out = The amount of solute deposited

Which gives;

Amount of solute deposited = 7.613 moles - 1.79 moles = 5.823 moles

The molar mass of Pb(NO₃)₂ = 207 g + 2 × (14 g + 3 × 16 g) = 331 g

The molar mass of Pb(NO₃)₂ = 331 g/mol

The amount of solute deposited = Number of moles × Molar mass

Which gives;

The amount of solute deposited = 5.823 moles × 331 g/mol =<u> 1,927.413 g </u>

Learn more about saturated solutions here:

brainly.com/question/2624685

5 0
2 years ago
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