Answer:
hello the molecules are missing from your question below are the Generic molecules :
and 
answer : It can be determined that both generic molecules are polar
It can be determined that both generic molecules have similar molecular shape
They have different Geometry
They differ in bond angles as well
Explanation:
The two generic molecules :
and 
comparing(similarities) these two generic molecules
It can be determined that both generic molecules are polar
It can be determined that both generic molecules have similar molecular shape
differences between the generic molecules
They have different Geometry
They differ in bond angles as well
Answer:
11.6mL of the 0.1400M NaOH solution
Explanation:
<em>0.154g of chloroacetic acid diluted to 250mL. Titrated wit 0.1400M NaOH solution.</em>
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The reaction of chloroacetic acid, ClCH₂COOH (Molar mass: 94.5g/mol) with NaOH is:
ClCH₂COOH + NaOH → ClCH₂COO⁻ + Na⁺ + H₂O
<em>Where 1 mole of the acid reacts per mole of the base.</em>
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That means the student will reach equivalence point when moles of chloroacetic acid = moles NaOH.
You will titrate the 0.154g of ClCH₂COOH. In moles (Using molar mass) are:
0.154g ₓ (1mol / 94.5g) = <em>1.63x10⁻³ moles of ClCH₂COOH</em>
To reach equivalence point, the student must add 1.63x10⁻³ moles of NaOH. These moles comes from:
1.63x10⁻³ moles of NaOH ₓ (1L / 0.1400moles NaOH) = 0.0116L of the 0.1400M NaOH =
<h3>11.6mL of the 0.1400M NaOH solution</h3>
2[H⁺] + [O²⁻] → H₂O
Explanation:
Half reactions are usually composed of components of oxidation-reduction (redox) reaction where one element is losing electrons while another is gaining so they can come together into a compound. The half-reaction shows part of a reaction where the combining elements are charged and the product, from the redox, is neutral.
In this case, the H⁺ is carrying the positive charge because it is donating an electron to O²⁻, which is the reason the O²⁻ is carrying the negative charge. Note that we need 2 H⁺ for every one O²⁻. The O is being reduced while the H is being oxidized.
Learn More:
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Answer: Yes. That is right. The actual answer, not rounded, would be 12.7778 Degrees Celsius.
We are given the pOH of the solution of 10.75. pOH is the property of the solution that is related to the OH ion concentration of the solution. THe formula to be followed is pOH = -log (OH); OH- = 10^-pOH. In this case, OH- = 10^-10.75 equal to B. 1.778 x 10^-11 M