Answer:
Empirical formula = NO₂
Molecular formula = N₂O₄
Explanation:
Percentage mass of Nitrogen = 30.4 %
Percentage mass of Oxygen = 60.9 %
Mole ratio of the elements:
Nitrogen = 30.4/14 = 2.17
Oxygen = 69.9/16 = 4.37
Dividing by the smallest ratio to obtain a simple ratio
Nitrogen: 2.17/2.17 = 1
Oxygen; 4.37/2.17 = 2
Therefore, the simplest mole ratio is 1:2
Empirical formula = NO₂
Molecular formula = n(empirical formula), therefore, molecular mass = n *(empirical mass)
92.010 = n(14 + 32)
92.010 = 46n
n = 92.010/46
n = 2
Therefore, molecular formula = 2(NO₂)
Molecular formula = N₂O₄
