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yKpoI14uk [10]
3 years ago
10

Determine the mass of hydrogen chloride needed to react completely with 12.8 g of aluminum to produce aluminum chloride and hydr

ogen gas.
Chemistry
1 answer:
Hoochie [10]3 years ago
5 0
First write out the eqn, and balance it.

next, take 12.8g/mr of aluminium
this will give u the mols of aluminium

next, take the ratio of HCL and Al, compare and find the mols of HCL.

take the mols of HCL/mr of HCL to give u mass

doneee
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Mrac [35]

7 would be correct because I divide it

8 0
3 years ago
Can someone tell me how to draw a atomic model for Cd
tensa zangetsu [6.8K]

Explanation:

there you go you can just look up atomic model for CD and click images

5 0
3 years ago
How do the Carnivorous plants survive without soil?
Mkey [24]
Answer:

Carnivorous plants are easy to grow, if you follow a few, simple rules.

Wet all of the time.
Mineral-free water.
Mineral-free soil.
Lots of light.


Wet all of the time.
Carnivorous plants are native to bogs and similar nutrient-poor habitats. As a consequence, the plants live in conditions that are constantly damp. To grow healthy carnivorous plants, it is important to duplicate their habitat as closely as possible. Keep the soil wet or at least damp all of the time. The easiest way to do this is use the tray method. Set the pots in a tray or saucer, and keep water in it at all times. Pitcher plants can grow in soggy soil with the water level in the saucer as deep as 1/2 the pot, but most carnivorous plants prefer damp to wet soil, so keep the water at about 1/4 inch and refill as soon as it is nearly gone. Water from below, by adding water to the tray, rather than watering the plant. This will avoid washing away the sticky muscilage of the sundews and butterworts and keep from closing the flytraps with a false alarm.


Mineral-free water.
Always use mineral-free water with your carnivorous plants, such as rainwater or distilled water. Try keeping a bucket near the downspout to collect rainwater. Distilled water can be purchased at the grocery store, but avoid bottled drinking water. There are simply too many minerals in it. The condensation line from an air conditioner or heat pump is another source of mineral-free water. Reverse-osmosis water is fine to use. Carnivorous plants grow in nutrient poor soils. The minerals from tap water can “over-fertilize” and “burn out” the plants. In a pinch, tap water will work for a short while, but flush out the minerals with generous portions of rainwater, when it is available.


Mineral-free soil.
The nutrient poor soils to which the carnivorous plants have adapted are often rich in peat and sand. This can be duplicated with a soil mixture of sphagnum peat moss and horticultural sand. Be sure to check the peat label for sphagnum moss. Other types will not work well. The sand should be clean and washed. Play box sand is great, and so is horticultural sand. Avoid “contractor’s sand” which will contain fine dust, silt, clay and other minerals. Never use beach sand or limestone based sand. The salt content will harm the plants. The ratio of the mix is not critical, 1 part peat with 1 part sand works well for most carnivorous plants. Flytraps prefer a bit more sand, and nepenthes prefer much more peat. Use plastic pots, as terra cotta pots will leach out minerals over time and stress your plants.

Explanation:


Kayo na Po bahala magpaigsi
5 0
2 years ago
If 0.0106 g of a gas dissolves in 0.792 L of water at 0.321 atm, what quantity of this gas (in grams) will dissolve at 5.73 atm?
Alex73 [517]

Answer:

0.189 g.

Explanation:

  • This problem is an application on <em>Henry's law.</em>
  • Henry's law states that the solubility of a gas in a liquid is directly proportional to its partial pressure of the gas above the liquid.
  • Solubility of the gas ∝ partial pressure
  • If we have different solubility at different pressures, we can express Henry's law as:

<em>S₁/P₁ = S₂/P₂,</em>

S₁ = 0.0106/0.792 = 0.0134 g/L and P₁ = 0.321 atm

S₂ = ??? g/L and P₂ = 5.73 atm

  • So, The solubility of the gas at 5.73 atm (S₂) = S₁.P₂/P₁ = (0.0134 g/L x 5.73 atm) / (0.321 atm) = 0.239 g/L.

<em>The quantity in (g) = S₂ x V = (0.239 g/L)(0.792 L) = 0.189 g.</em>

<em></em>

8 0
3 years ago
What is the frequency of a wave with a wavelength of 6.40x10^4 meters?
yKpoI14uk [10]

Answer:

frequency = 0.47×10⁴ Hz

Explanation:

Given data:

Wavelength of wave = 6.4× 10⁴ m

Frequency of wave = ?

Solution:

Formula:

Speed of wave = wavelength × frequency

Speed of wave = 3 × 10⁸ m/s

Now we will put the values in formula.

3 × 10⁸ m/s = 6.4× 10⁴ m × frequency

frequency = 3 × 10⁸ m/s / 6.4× 10⁴ m

frequency = 0.47×10⁴ /s

s⁻¹ = Hz

frequency = 0.47×10⁴ Hz

Thus the wave with wavelength of 6.4× 10⁴ m have 0.47×10⁴ Hz frequency.

4 0
3 years ago
Read 2 more answers
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