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yKpoI14uk [10]
3 years ago
10

Determine the mass of hydrogen chloride needed to react completely with 12.8 g of aluminum to produce aluminum chloride and hydr

ogen gas.
Chemistry
1 answer:
Hoochie [10]3 years ago
5 0
First write out the eqn, and balance it.

next, take 12.8g/mr of aluminium
this will give u the mols of aluminium

next, take the ratio of HCL and Al, compare and find the mols of HCL.

take the mols of HCL/mr of HCL to give u mass

doneee
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Answer:

1.13 x 10²⁴formula units

Explanation:

Given parameters:

Number of moles of NH₄Cl = 1.87mol

Unknown:

Number of formula units = ?

Solution:

From mole concept;

     1 mole of a substance contains 6.02 x 10²³ formula units

Now;

    1.87 moles of  NH₄Cl   1.87 x 6.02 x 10²³ = 1.13 x 10²⁴formula units

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Calculate the standard enthalpy of formation of carbon disulfide (CS2) from it's elements, given that C(graphite) + O2(g) → CO2(
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Answer:

Standard enthalpy of formation of Carbon disulfide CS2 = 87.3 KJ/mol

Explanation:

forming CS2 means that it should in the product side

C(graphite) + O2 → CO2                  ΔH = -393.5

2S(rhombic) + 2O2 → 2SO2            ΔH = -296.4 x 2

CO2 + 2SO2 → CS2 + 3O2             ΔH = -1073.6 x -1

the second reaction is multiplied by 2 so that the SO2 and O2 can cancel out.

the third reaction is reversed (multiplied by -1) so that CS2 will be on the product side.

after adding the reaction and cancelling out similarities, the final reaction is: C(graphite) + 2S(rhombic) → CS2

Add ΔH to find the enthalpy of formation of CS2

ΔHf = (-393.5) + (-296.4 x 2) + (-1073.6 x -1) = 87.3 KJ/mol

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4 0
3 years ago
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