Answer:
Because a molecule, by definition, has a valence of zero
(neutral charge, stable). Also by definition, an ion has a positive
or negative charge or valence and is not stable.
Explanation:
Answer:
The atomic number is the number of the elements inside the periodic table and the mass is the weight or a number under the elements.
Explanation:
Correct me if I am wrong
Answer:
D
Explanation:
Hopefully this helps you!
This element is found in group 3A, period 3
<h3>Further explanation
</h3>
The maximum number of electrons that can be filled in the nth electron shell is 2n²(n=shell)
-
K shell (n = 1) maximum 2 x 1² = 2 electrons
- L shell (n = 2) maximum 2 x 2² = 8 electrons
- M shell (n = 3) maximum 2 x 3² = 18 electrons
- N shell (n = 4) maximum 2 x 4² = 32 electrons
Electron configuration of element X : 2.8.3 , so :
K shell = 2 ⇒1s²
L shell = 8⇒2s²2p⁶
M shell = 3⇒ 3s²3p¹
Block p: group 13-18 (has a 2p-6p configuration), also called a representative element because it includes metals, non-metals and metalloids
The outer shell 3s²3p¹ : located in group 3A and period 3
group⇒valence electron ⇒3
period⇒the greatest value of the quantum number n⇒3
Answer:
HX (aq) + H₂O (l) ⇄ H₃O⁺ (aq) + X⁻ (aq)
Acid Base Conj. acid Conj. base
Explanation:
The equation is:
HX (aq) + H₂O (l) ⇄ H₃O⁺ (aq) + X⁻ (aq)
This is the typical equilibrium for a weak acid. It would complete if we notice the Ka.
HX (aq) + H₂O (l) ⇄ H₃O⁺ (aq) + X⁻ (aq) Ka
1 mol of hypothetic HX acid react to 1 mol of water in order to release a proton and make hydronium and generate the X⁻ anion.
HX will be the acid, in this case a weak one and water will be the base. Water is able to accept a proton to make itslef hydronium
Hydronium is the conjugate acid.
The X⁻ will be the conjugate strong base.
This ion can generate the acid form again, that's why it is strong, because it can make hydrolisis.
X⁻ (aq) + H₂O (l) ⇄ HX (aq) + OH⁻(aq) Kb
In this case, the anion will be the conjugate base which it takes a proton from water (acid form) to make a conjugate acid, the HX and a conjugate base, OH⁻
