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artcher [175]
2 years ago
8

Which part of the cell is affected by the movement of molecules through diffusion, osmosis, and active transport? A.Cell membran

e B.Cytoplasm C.Chromosome D.Cell wall
Chemistry
1 answer:
Serjik [45]2 years ago
6 0

Answer:

membrana celular

Explanation:

El transporte celular es el intercambio de sustancias a través de la membrana plasmática, que es una membrana semipermeable.1​

El transporte es importante para la célula porque le permite expulsar de su interior los desechos del metabolismo, también el movimiento de sustancias que sintetiza como hormonas. Además, es la forma en que adquiere nutrientes mediante procesos de incorporación a la célula de nutrientes disueltos en el agua. Las vías de transporte a través de la membrana celular y los mecanismos básicos para las moléculas de pequeños tamaños son:

Índice

1 Transporte pasivo

1.1 Ósmosis

1.1.1 Ósmosis en una célula animal

1.1.2 Ósmosis en una célula vegetal

1.2 Difusión facilitada

2 Transporte activo

2.1 Transporte activo primario: Bomba de sodio y potasio o Bomba Na+/K+

2.2 Transporte activo secundario o cotransporte

3 Transporte en masa

3.1 Endocitosis

3.2 Exocitosis

4 Véase también

5 Referencias

6 Enlaces externos

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Look at the diagram of a fuel cell below.
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What is one chemical reaction that begins with petroleum as a starting material
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Answer:

Thermal decomposition or cracking

Explanation:

Petroleum is a mixture of hydrocarbons which are usually formed naturally. Petroleum undergo a host of chemical reactions. One of such is thermal decomposition or cracking.

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6 0
3 years ago
Explain how carbon is conserved in the carbon cycle.
Sonja [21]

Most of the carbon is put away in sedimentary carbonates and kerogens, with the rest being spread between the sea, the air, biomass, for example, plants and creatures, and petroleum products

<u>Explanation</u>:

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4 years ago
A sample of gas contains 0.1800 mol of CO(g) and 0.1800 mol of NO(g) and occupies a volume of 23.2 L. The following reaction tak
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Answer:

The volume of the sample is 17.4L

Explanation:

The reaction that occurs requires the same amount of CO and NO. As the moles added of both reactants are the same you don't have any limiting reactant. The only thing we need is the reaction where 4 moles of gases (2mol CO + 2mol NO) produce 3 moles of gases (2mol CO2 + 1mol N2). The moles produced are:

0.1800mol + 0.1800mol reactants =

0.3600mol reactant * (3mol products / 4mol reactants) = 0.2700 moles products.

Using Avogadro's law (States the moles of a gas are directly proportional to its pressure under constant temperature and pressure) we can find the volume of the products:

V1n2 = V2n1

<em>Where V is volume and n moles of 1, initial state and 2, final state of the gas</em>

Replacing:

V1 = 23.2L

n2 = 0.2700 moles

V2 = ??

n1 = 0.3600 moles

23.2L*0.2700mol = V2*0.3600moles

17.4L = V2

<h3>The volume of the sample is 17.4L</h3>
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