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Viktor [21]
3 years ago
11

Vapor pressure is related to the temperature of the liquid. user: in an open system, the vapor pressure is equal to the _____. i

nside air pressure outside air pressure inside temperature outside temperature
Physics
2 answers:
Naddik [55]3 years ago
8 0
In an open system the vapor pressure of a liquid, if it is not boliling is less thatn the atmospheric pressure.

As the temperature of the liquid increases, the vapor pressure increases. When the vapor pressure equals the atmospheric pressure the molecules of liquid escape and the liquid boils. The temperature at which this happens is the boiling point.
iVinArrow [24]3 years ago
6 0

Answer

-Directly;  outside air pressure

Vapor pressure is directly related to the temperature of the liquid. user: in an open system, the vapor pressure is equal to the outside air pressure.

Explanation;

-As the temperature of a system increases, the average kinetic energy of the molecules increases in both the liquid and gas phases.

-A higher average kinetic energy facilitates the escape of molecules from the liquid phase into the gas phase. At the same time, the rate of return of gas phase molecules to the liquid also increases. A new equilibrium point is reached at a higher gaseous vapor pressure. The increase in vapor pressure with temperature is exponential.


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A spherical balloon has a radius of 7.40 m and is filled with helium. Part A How large a cargo can it lift, assuming that the sk
malfutka [58]

Answer:

The mass of the cargo is M  =  188.43 \ kg

Explanation:

From the question we are told that

    The radius of the spherical balloon is  r =  7.40 \ m

     The mass of the balloon is  m = 990\ kg  

The volume of the spherical balloon is mathematically represented as

     V  =  \frac{4}{3} * \pi r^3

substituting values

      V  =  \frac{4}{3} * 3.142 *(7.40)^3

      V  =  1697.6 \ m^3

The total mass  the balloon can lift is mathematically represented as

     m =  V (\rho_h - \rho_a)

where \rho_h is the density of helium with a  value of

       \rho_h  =  0.179 \ kg /m^3

and  \rho_a is the density of air with a value of

        \rho_ a  = 1.29 \ kg / m^3

substituting values

          m =  1697.6 ( 1.29  - 0.179)

         m =  1886.0  \ kg

Now the mass of the cargo is mathematically evaluated as

        M  =  1886.0 - 1697.6

        M  =  188.43 \ kg

       

5 0
3 years ago
Two loudspeakers are placed 1.8 m apart. They play tones of equal frequency. If you stand 3.0 m in front of the speakers, and ex
Ahat [919]

The question is incomplete. The complete question is :

Two loudspeakers are placed 1.8 m apart. They play tones of equal frequency. If you stand 3.0 m in front of the speakers, and exactly between them, you hear a minimum of intensity. As you walk parallel to the plane of the speakers, staying 3.0 m away, the sound intensity increases until reaching a maximum when you are directly in front of one of the speakers. The speed of sound in the room is 340 m/s.

What is the frequency of the sound?

Solution :

Given :

The distance between the two loud speakers, d = 1.8 \ m

The speaker are in phase and so the path difference is zero constructive interference occurs.

At the point D, the speakers are out of phase and so the path difference is $=\frac{\lambda}{2}$

Therefore,

$AD-BD = \frac{\lambda}{2}

$\sqrt{(1.8)^2+(3)^2-3} =\frac{\lambda}{2}$

$\lambda = 2 \times 0.4985$

$\lambda = 0.99714 \ m$

Thus the frequency is :

$f=\frac{v}{\lambda}$

$f=\frac{340}{0.99714}$

f=340.9744 Hz

3 0
2 years ago
If you are pushing on a crate on a frictionless surface in one direction, and your friend is pushing on the crate in the opposit
liberstina [14]

Answer:

Its not A..

Explanation:

I chose A - was incorrect

3 0
3 years ago
True or False: The energy increase of an object acted on only by a gravitational force is equal to the product of the object's w
tamaranim1 [39]

Answer:

False.

Explanation:

The statement shown in the question above is false and this can be confirmed by Newton's law on universal gravitation. According to Newton, the gravitational force exerted on any body is proportional to its weight, but the distance that the object travels when falling is disproportionate. In addition, if the force resulting from the weight of the object and its displacement has an angle of 0º, the weight force of that object will provide an increase in kinetic energy.

4 0
3 years ago
Cierto volumen de gas se encuentra a 60°c de temperatura y 5atm de presión, es calentado hasta 140°c, estado en el cual ocupa un
earnstyle [38]

Answer:

V1 = 2221.33 L

Explanation:

The system is about a ideal gas. Then you can use the equation for ideal gases for a volume V1, temperature T1 and pressure P1:

P_1V_1=nRT_1   (1)

And also for the situation in which the variables T, V and P has changed:

P_2V_2=nRT_2   (1)

R: constant of ideal gases = 0.082 L.atm/mol.K

For both cases (1) and (2) the number of moles are the same. Next, you solve for n in (1) and (2):

n=\frac{P_1V_1}{RT_1}\\\\n=\frac{P_2V_2}{RT_2}

Next, you equal these equations an solve for T2:

\frac{P_1V_1}{RT_1}=\frac{P_2V_2}{RT_2}\\\\V_1=\frac{P_2V_2T_1}{P_1T_2}

Finally you replace the values of P2, V2, T1 and T2:

V_1=\frac{(7atm)(680L)(140\°C)}{(60\°C)(5atm)}=2221.33\ L

Hence, the initial volume of the gas is 2221.33 L

5 0
3 years ago
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