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Anika [276]
3 years ago
6

Some lenses are shaped with one flat side and one spherically-shaped side. This shape is designed to focus parallel light rays o

nto a single point. In a few sentences, explain how the spherical shape of the lens' surfaces causes parallel light rays to focus on a single point. (Assume the light is travelling through air into a lens with an index of refraction greater than that of air.) g
Physics
1 answer:
Komok [63]3 years ago
7 0

Answer:

Some lenses are used to focus light to a pre-defined point based on the amount of curvature of their surfaces.

In a piano design convex, some surfaces are flat while others has positive lenses (biconvex)

Explanation:

Solution

These lenses are applied to pay attention to light in a  point pre-defined  based on the amount of curvature of their surfaces.

For that of a plano-convex design, one surface has a positive curve and for biconvex lenses, both surfaces are positively curved while the other  remains flat.

when used practically, plano-convex lenses are most commonly used where the object being imaged is far apart from lens.

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Marina86 [1]

Answer:

I think It Should be Star B

Explanation:

6 0
3 years ago
Read 2 more answers
Calculate the displacement of the volleyball in sample problem 2f when teh volleyballs final velocity is 1.1 m/s upward
stich3 [128]
We have: v i (initial velocity) = 6 m/sv = 1.1 m/sa = - 9.8 m/s²v = v i + a · t1.1 m/s = 6 m/s - 9.8 m/s² t9.8 t = 6 - 1.19.8 t = 4.9t = 4.9 : 9.8t = 0.5 sThen the replacement:x = xi + vi · t + a t² / 2( xi = 0 )x = 6 · 0.5 - 9.8 · 0.25 / 2x = 3 - 1.225Answer:
x = 1.775 m

4 0
4 years ago
A car weighing 9800 N travels at 30 m/s. What braking force brings it to rest in 100m? In 10 m?
Svetach [21]

As per kinematics equation we know that

final speed of the car = 0 m/s

initial speed is given as 30 m/s

distance moved = 100 m

now we have

v_f^2 - v_i^2 = 2 a d

0 - 30^2 = 2(a)(100)

a = - 4.5 m/s^2

now braking force is given as

F = ma

now for mass we know that the weight of car is

W = mg = 9800 N

so mass of car is

m = 1000 kg

now we have

F = 1000(4.5) = 4500 N

Part b)

Again we have

final speed of the car = 0 m/s

initial speed is given as 30 m/s

distance moved = 10 m

now we have

v_f^2 - v_i^2 = 2 a d

0 - 30^2 = 2(a)(10)

a = - 45 m/s^2

now braking force is given as

F = ma

mass of car is

m = 1000 kg

now we have

F = 1000(45) = 45000 N

4 0
3 years ago
Kalisha is going to cut the remaining 21 1/2 buns into thirds. How many 1/3 size buns will she have?
baherus [9]
Total buns = 21 1/2 = 43/2 buns
1/3 size buns would be: 43/2 / 1/3 = 43*3 / 2 = 129/2

In short, Your Answer would be 129/2 or 64 1/2 or 64.5

Hope this helps!
6 0
3 years ago
Read 2 more answers
A car moving at 11.6 m/s begins to accelerate at 5.22 m/s/s and reaches a final velocity of 31.5 m/s. How far did it travel duri
mr_godi [17]

Use the kinematic equation,

Vf^2 = Vi^2 + 2aX

31.5^2 = 11.6^2 + 2(5.22)(x)

Solve for x

Answer: 82.2m

8 0
3 years ago
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