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ira [324]
3 years ago
11

A digital speedometer constantly reads zero mph. Technician A says the problem may be the vehicle speed sensor. Technician B say

s the problem may be the throttle position sensor. Who is correct
Physics
1 answer:
uysha [10]3 years ago
4 0

Answer:

Technician A

Explanation:

The vehicle speed sensor is located at the right side of the transmission near the output shaft, it is also known as the output speed sensor.it is what tells your vehicle control unit how fast it is going. The vehicle speedometer and odometer rely on the information from this sensor.

With a faulty speed sensor ,you might not be able to know how fast your car is going.

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A current of 9 A flows through an electric device with a resistance of 43 Ω. What must be the applied voltage in this particular
lubasha [3.4K]

Voltage, V = IR

Where I is current in Ampere, R is Resistance in Ohms.

V = 9A * 43 Ω

V = 387 V

8 0
3 years ago
Helppppppppppppppp asappppppppppppp
vichka [17]
The answer to the problem b.
8 0
3 years ago
If you can’t open the lid of a jelly jar what should you do?
9966 [12]

If I can't open the lid of a jelly jar, I'd keep trying and if I can't open the lid of a jelly jar after the MANY tries I took, I'd ask for help.

6 0
3 years ago
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The second-order decomposition of hi has a rate constant of 1.80 x 10−3 m−1 s−1. How much hi remains after 45.6 s if the initial
zlopas [31]

Answer:

2.9 M

Explanation:

The concentration-time equation for a second order reaction is:

1/[A] = kt + 1/[A°]

Where,

A = concentration remaining at time, t

A° = initial concentration

k = rate constant

1/[A] = (1.80 x 10^-3) * (45.6) + 1/3.81

1/[A] = 0.345

= 1/0.345

= 2.9 M.

6 0
2 years ago
A 0.49-kg cord is stretched between two supports, 7.8m apart. When one support is struck by a hammer, a transverse wave travels
katovenus [111]

To solve this problem we will apply the laws of Mersenne. Mersenne's laws are laws describing the frequency of oscillation of a stretched string or monochord, useful in musical tuning and musical instrument construction. This law tells us that the velocity in a string is directly proportional to the root of the applied tension, and inversely proportional to the root of the linear density, that is,

v = \sqrt{\frac{T}{\mu}}

Here,

v = Velocity

\mu= Linear density (Mass per  unit length)

T = Tension

Rearranging to find the Period we have that

T = v^2 \mu

T = v^2 (\frac{m}{L})

As we know that speed is equivalent to displacement in a unit of time, we will have to

T = (\frac{L}{t}) ^2(\frac{m}{L})

T = (\frac{7.8}{0.83})^2 (\frac{0.49}{7.8})

T = 5.54N

Therefore the tension is 5.54N

8 0
2 years ago
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