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ira [324]
4 years ago
11

A digital speedometer constantly reads zero mph. Technician A says the problem may be the vehicle speed sensor. Technician B say

s the problem may be the throttle position sensor. Who is correct
Physics
1 answer:
uysha [10]4 years ago
4 0

Answer:

Technician A

Explanation:

The vehicle speed sensor is located at the right side of the transmission near the output shaft, it is also known as the output speed sensor.it is what tells your vehicle control unit how fast it is going. The vehicle speedometer and odometer rely on the information from this sensor.

With a faulty speed sensor ,you might not be able to know how fast your car is going.

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Which of the following is an example of the concepts of growth and development functioning together?   
DedPeter [7]
Hello there.

<span>Which of the following is an example of the concepts of growth and development functioning together?   <span>
</span>
</span><span>  C. Children learning to print their names 
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7 0
3 years ago
A 0.366 kg metal cylinder is placed inside the top of a plastic tube, the lower end of which is sealed off by an adjustable plun
DochEvi [55]

Answer:

a = 32.6 m/s^2

Explanation:

As we know that pressure between the cylinder and plunger is increased by 1.59 times

So this will make a net force upwards on the cylinder which is given as

F = \Delta P A

now we will have

\Delta P = P_2 - P_1

Here initial pressure is given as

P_1 = P_o + \frac{mg}{A}

now new pressure is given as

P_2 = 1.59 P_1

so we have force on the cylinder given as

F = P_2A - mg - P_oA

F = 1.59(P_0 + \frac{mg}{A})A - (mg + P_0A)

F = 0.59(1.01 \times 10^5 \times \pi(7.24 \times 10^{-3})^2  + 0.366(9.81))

F = 11.93 N

now the acceleration is given as

F = ma

11.93 = 0.366 a

a = 32.6 m/s^2

4 0
3 years ago
A rod (length = 80 cm) with a rectangular cross section (1.5 mm × 2.0 mm) has a resistance of 0.20 Ω. What is the resistivity of
Andru [333]

Answer:

The resistivity of the material used to make the rod is ρ= 7.5 * 10⁻⁷ Ω.m

Explanation:

R= 0.2 Ω

L= 0.8 m

S= 1.5mm*2mm= 3 mm² = 3 * 10⁻⁶ m²

ρ = (R*S)/L

ρ= 7.5 * 10⁻⁷ Ω.m

7 0
3 years ago
One of the most important properties of materials in many applications is strength. Two of the qualitative measures of the stren
katrin2010 [14]

To solve this exercise it is necessary to take into account the concepts related to Tensile Strength and Shear Strenght.

In Materials Mechanics, generally the bodies under certain loads are subject to both Tensile and shear strenghts.

By definition we know that the tensile strength is defined as

\sigma = \frac{F}{A}

Where,

\sigma =Tensile strength

F = Tensile Force

A = Cross-sectional Area

In the other hand we have that the shear strength is defined as

\sigma_y = \frac{F_y}{A}

where,

\sigma_y =Shear strength

F_y = Shear Force

A_0 =Parallel Area

PART A) Replacing with our values in the equation of tensile strenght, then

311*10^6 = \frac{F}{(15*10^{-6})(30*10^{-2})}

Resolving for F,

F= 1399.5N

PART B) We need here to apply the shear strength equation, then

\sigma_y = \frac{F_y}{A}

210*10^6 = \frac{F_y}{15*10^{-6}30*10^{-2}}

F_y = 945N

In such a way that the material is more resistant to tensile strength than shear force.

6 0
3 years ago
A particle moves along the x axis from the origin. The magnitude of the position vector at time t is
Maurinko [17]

1) The average velocity is -2.1\cdot 10^5 m/s

2) The instantaneous velocity is 64t-260t^3

Explanation:

1)

The average velocity of an object is given by

v=\frac{d}{t}

where

d is the displacement

t is the time elapsed

In this problem, the position of the particle is given by the function

x(t) = 32t^2 - 65t^4

where t is the time.

The position of the particle at time t = 6 sec is

x(6) = 32(6)^2 - 65(6)^4=-83,088 m

While the position at time t = 12 sec is

x(12)=32(12)^2-65(12)^4=-1,343,232 m

So, the displacement is

d=x(12)-x(6)=-1,343,232-(-83,088)=-1,260,144 m

And therefore the average velocity is

v=\frac{-1,260,144 m}{12 s- 6 s}=-2.1\cdot 10^5 m/s

2)

The instantaneous velocity of a particle is given by the derivative of the position vector.

The position vector is

x(t) = 32t^2 - 65t^4

By differentiating with respect to t, we find the velocity vector:

v(t) = x'(t) = 2\cdot 32 t - 4\cdot 65 t^3 = 64t - 260 t^3

Therefore, the instantaaneous velocity at any time t can be found by substituting the value of t in this expression.

Learn more about velocity:

brainly.com/question/5248528

#LearnwithBrainly

6 0
4 years ago
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