Question

The manufacturer's price for a cooler is $28.50 A camping store that buys the coolers sells them for $40.76 What is the approximate percent of increase in the price of the coolers?.... might have to zoom in

Answer 1

The percent of the increase is

$I=\frac{N-O}{O}\times100$

I is the increasing value

N is the new value

O is the original value

The price of the cooler is $28.50, then

O = 28.50

The selling price of the cooler is $40.76, then

N = 40.76

We will substitute them in the rule above to find I

$I=\frac{40.76-28.50}{28.50}\times100$

Let us calculate it

I = 43.0175 %

Round it to the nearest percent

I = 43%

The answer is D