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Keith_Richards [23]
1 year ago
11

Critical Thinking 1. One day, a group of neighbourhood degs Started barking on their own. The residents living in that area are

left wondering what provoked the dogs to bark. What could be the reason?​
Physics
1 answer:
liberstina [14]1 year ago
3 0

The reason behind the barking of the group of neighborhood dogs could be <u>Territorial/Protective</u> or  <u>Alarm/Fear</u>.

What is bark or barking?

Dogs are known for making the most prevalent barking noises. Wolves, coyotes, foxes, seals, and barking owls are a few other creatures that make this sounds. The most typical onomatopoeia for this sound in English, particularly for large dogs, is "woof." The word "bark" can also be used to describe the sound made by numerous canids. A bark is a brief vocalization, as per the researchers at the University of Massachusetts Amherst.

Territorial/Protective: When a person or another animal enters their perceived area, your dog may bark excessively, depending on the breed. The barking frequently gets louder as the threat draws closer. When your dog barks in this manner, he will appear vigilant and sometimes even hostile.

Alarm/Fear: Some dogs will bark in alarm or fear at any sound or item that draws their attention or alarmed them. It's not just in their home country where this can occur. When they are afraid, their tails will be tucked and their ears will be pulled back.

To know more about bark, go to link

brainly.com/question/5082728

#SPJ9

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A suspension bridge has twin towers that are 1300 feet apart. Each tower extends 180 feet above the road surface. The cables are
zhannawk [14.2K]

Answer:

y = 17.04 ft

Explanation:

Since the cable touches the road at the mid point of two towers

so here we have vertex at that mid point taken to be origin

now the maximum height on the either side is given as

y = 180 ft

horizontal distance of the tower from mid point is given as

x = \frac{1300}{2} = 650 ft

now from the equation of parabola we have

y = k x^2

180 = k(650^2)

k = 4.26 \times 10^{-4}

now we have

y = (4.26 \times 10^{-4})x^2

now we need to find the height at distance of 200 ft from center

so we have

y = (4.26 \times 10^{-4})(200^2)

y = 17.04 ft

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Ghella [55]
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alukav5142 [94]

Answer:

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In our case having a fundamental wave of 100Hz, I can have harmonics of 200,300,400, ..., 600Hz

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