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Sergio039 [100]
3 years ago
11

(1) In nondestructive testing, a discontinuity may be defined as an interruption in the normal physical structure or configurati

on of a part.(2) A discontinuity may or may not affect the usefullness of a part.Which statement(s) are true?
Physics
1 answer:
QveST [7]3 years ago
4 0

Answer: BOTH ARE TRUE

Explanation: Nondestructive testing or Evaluation is a term used in the field of science and technology to describe the evaluations, analysis or testing carried out on components of materials without destroying any part or components of the test materials. It is very useful in scientific research or industrial engineering environments. When any disruption of physical structure or configuration of a component will lead to discontinuing of the test, and it may not affect the usefulness of the affected parts.

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How are reversibility, time, and entropy connected
kondor19780726 [428]

Answer:

As one goes "forward" in time, the second law of thermodynamics says, the entropy of an isolated system can increase, but not decrease. ... Thus, entropy measurement is a way of distinguishing the past from the future.

Explanation:

6 0
3 years ago
You are travelling by skateboard at 3.0 m/s and start to accelerate. If you
vovangra [49]

Answer: 8m/s

Explanation:

Vs= 3 m/s

Vf=?

a=0.5m/s²

t=10s

-----------

a=Vf-Vs/t

at=Vf-Vs

0.5*10s=Vf-Vs

5m/s=Vf-3m/s

5m/s+3m/s=Vf

Vf=8m/s

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3 years ago
The electric power consumed by a circuit with one light bulb is 24 W. The voltage of the battery is 3 V. What is the current in
IceJOKER [234]

Answer:

8 ampere

Explanation:

P= V x I

so

I = P/V

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I = 8 A

5 0
3 years ago
A particle that is moving along a straight line accelerates from 40 cm/s to 20 cm/s in 5.0 s and then has a constant acceleratio
Marrrta [24]

Answer:

Average speed,  v_{avg}=43.33\ \rm cm/s

Explanation:

Given:

  • Initial speed, u=40 cm/s
  • final speed , v=20 cm/s
  • Time taken, t=5 s

<u>First case</u>

Using equation of motion we have

2as=v^2-u^2\\2as=20^2-40^2\\as=-600\\

Now using,

v=u +at\\20=40+a\times5\\a=-4\ \rm cm/s^2

now putting the value of a in first equation we get

s=150\ \rm cm

<u>Second case</u>

Accelerationa=20\ \rm cm/s^2

Time taken t=4\ \rm s

using equation of motion in one Dimension we have

s=ut+\dfrac{at^2}{2}\\\\s=20\ties 4+\dfrac{20\times 4^2}{2}\\s=240\ \rm cm

Average speed is equal to total distance travelled per unit total time taken

v_{avg}=\dfrac{150+240}{5+4}\\v_{avg}=43.33\ \rm cm/s

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4 years ago
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What’s the equalibrium rule?
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The vector sum of forces acting on a non-accelerating object equals zero.
equation form: ΣF = 0
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3 years ago
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