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Sergio039 [100]
3 years ago
11

(1) In nondestructive testing, a discontinuity may be defined as an interruption in the normal physical structure or configurati

on of a part.(2) A discontinuity may or may not affect the usefullness of a part.Which statement(s) are true?
Physics
1 answer:
QveST [7]3 years ago
4 0

Answer: BOTH ARE TRUE

Explanation: Nondestructive testing or Evaluation is a term used in the field of science and technology to describe the evaluations, analysis or testing carried out on components of materials without destroying any part or components of the test materials. It is very useful in scientific research or industrial engineering environments. When any disruption of physical structure or configuration of a component will lead to discontinuing of the test, and it may not affect the usefulness of the affected parts.

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Give the reason of evidence and claim.
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Answer:

it shows a black screen

Explanation:

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The formula without numbers is
xf = xi + vxi(t) +  \frac{1}{2} (a) {t}^{2}
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Miranda performed an experiment to determine what makes an object sink
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I guess the answer is

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A skateboarder traveling at 4.45 m/s can be stopped by a strong force in 1.82 s and by a weak force in 5.34 s.
ANTONII [103]

1) Impulse: -238.5 kg m/s

2) Strong force: -131.1 N, weak force: -44.7 N

Explanation:

1)

The impulse exerted on an object is equal to the change in momentum of the object itself.

Mathematically:

I=\Delta p=m(v-u)

where

m is the mass of the object

u is the initial velocity

v is the final velocity

For the skateboarder in this problem, we have:

m = 53.6 kg

u = 4.45 m/s

v = 0 (it comes to a stop)

Therefore, the impulse is

I=(53.6)(0-4.45)=-238.5 kg m/s

Where the negative sign indicates that the direction is opposite to the motion of the object.

2)

The impulse is also equal to the product between the force applied and the duration of the collision:

I=F\Delta t

where

I is the impulse

F is the average force

\Delta t is the time during which the force is applied

The strong force is applied in a time of

\Delta t = 1.82 s

Therefore this force is

F=\frac{I}{\Delta t}=\frac{-238.5}{1.82}=-131.1 N

The  weak force is applied in a time of

\Delta t = 5.34 s

So this force is

F=\frac{I}{\Delta t}=\frac{-238.5}{5.34}=-44.7 N

Learn more about impulse:

brainly.com/question/9484203

#LearnwithBrainly

6 0
3 years ago
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