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Virty [35]
3 years ago
7

Match the following rocks with the correct type.

Physics
2 answers:
slamgirl [31]3 years ago
6 0
I\B
2/A
3\C
4\E
5\D
6\F
I think this is right

Mila [183]3 years ago
4 0

The correct matches are:

1. obsidian - B) extrusive igneous;

2. granite - A) intrusive igneous;

3. conglomerate - C) clastic sedimentary;

4. evaporite - E) chemical sedimentary;

5. coal - D) organic sedimentary;

6. marble - F) metamorphic;

There are three big groups of rocks, igneous, sedimentary, and metamorphic. They further diversify into multiple types of rocks in accordance to their structure, chemical composition, crystallization, formation etc. The igneous can simple be divided into intrusive (ones that formed on the surface or very close to it) and extrusive (ones that formed deep into the ground). The sedimentary rocks can be divided into multiple groups in accordance to their composition, as some can be made of multiple sediments, some from organic material, some from mixture of sediments and organic material etc. And the metamorphic can simply be seen as rocks that come to be as a result of the transformation of the other two types if they are under big pressure and temperatures for longer periods of time.

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The answer is option B KE=1/2mv^2.

Reason:

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If you need anymore help feel free to ask me!

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A sliver cylindrical rod has a length of 0.5 m and a radius of 0.4 m, find the density of the rod if it's mass is 2.640 kg
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Density=10.50kg/m³

Explanation:

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2 years ago
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kolbaska11 [484]

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5 0
3 years ago
A long wire carrying a 5.0 A current perpendicular to the xy-plane intersects the x-axis at x= - 2.0 cm . A second, parallel wir
mario62 [17]

Answer:

a . 0.35cm

b.  11.33cm

Explanation:

a. Given both currents are in the same direction, the null point lies in between them. Let x be distance of N from first wire, then distance from 2nd wire is 4-x

#For the magnetic fields to be zero,the fields of both wires should be equal and opposite.They are only opposite in between the wires:

\frac{\mu_oi_1}{2\pi x}=\frac{\mu_oi_2}{2\pi(4-x)}\\\\5/x=\frac{3.5}{4-x}\\\\x=2.35cm\\\\N=2.35-2=0.35cm

Hence, for currents in same direction, the point is 0.35cm

b. Given both currents flow in opposite directions, the null point lies on the other side.

#For the magnetic fields to be zero,the fields of both wires should be equal and opposite.They are only opposite in outside the wires:

Let x be distance of N from first wire, then distance from 2nd wire is 4+x:

\frac{\mu_oi_1}{2\pi(4+ x)}=\frac{\mu_oi_2}{2\pi x}\\\\5/(4+x)=\frac{3.5}{x}\\\\x=9.33cm\\\\N=9.33+2=11.33cm

Hence, if currents are in opposite directions the point on x-axis is 11.33cm

8 0
3 years ago
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