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alexgriva [62]
3 years ago
5

A radio station's channel, such as 100.7 fm or 92.3 fm, is actually its frequency in megahertz (mhz), where 1mhz=106hz. calculat

e the broadcast wavelength of the radio station 104.9 fm.
Physics
1 answer:
lakkis [162]3 years ago
6 0
When it comes to wave behavior, there are parameters called wavelength and frequency. These two are related by speed of the radiowave. Radiowaves are electromagnetic waves which travels as fast as light. The wavelength is the distance while frequency is the reciprocal of time. When you multiply them both, you get the electromagnetic wave's speed. The equation is c = wavelength*frequency, where c is the speed of light equal to 3 x 10^8 m/s. 

3 x10^8 m/s = wavelength/104.9 x 10^6 Hz   (Hertz is 1/s)
wavelength = 2.86 meters
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Light waves are bent more easily than sound waves true or false
frez [133]
The answer is false
8 0
3 years ago
Which of think following materials is the best is the best choice for an insulating material?
RSB [31]
You are correct, the answer is C. 

Good insulators are materials that do not allow heat, electricity, light or sound pass through easily. Materials like steel and silver (which are metals) are not good insulators because they make good conductors. They easily allow heat, electricity and the like pass through them. 

Thus, the answer is letter C. Rubber. 
7 0
3 years ago
A flock of ducks is trying to migrate south for the winter, but they keep being blown off course by a wind blowing from the west
Minchanka [31]

The ducks' flight path as observed by someone standing on the ground is the sum of the wind velocity and the ducks' velocity relative to the wind:

ducks (relative to wind) + wind (relative to Earth) = ducks (relative to Earth)

or equivalently,

\vec v_{D/W}+\vec v_{W/E}=\vec v_{D/E}

(see the attached graphic)

We have

  • ducks (relative to wind) = 7.0 m/s in some direction <em>θ</em> relative to the positive horizontal direction, or

\vec v_{D/W}=\left(7.0\dfrac{\rm m}{\rm s}\right)(\cos\theta\,\vec\imath+\sin\theta\,\vec\jmath)

  • wind (relative to Earth) = 5.0 m/s due East, or

\vec v_{W/E}=\left(5.0\dfrac{\rm m}{\rm s}\right)(\cos0^\circ\,\vec\imath+\sin0^\circ\,\vec\jmath)

  • ducks (relative to earth) = some speed <em>v</em> due South, or

\vec v_{D/E}=v(\cos270^\circ\,\vec\imath+\sin270^\circ\,\vec\jmath)

Then by setting components equal, we have

\left(7.0\dfrac{\rm m}{\rm s}\right)\cos\theta+5.0\dfrac{\rm m}{\rm s}=0

\left(7.0\dfrac{\rm m}{\rm s}\right)\sin\theta=-v

We only care about the direction for this question, which we get from the first equation:

\left(7.0\dfrac{\rm m}{\rm s}\right)\cos\theta=-5.0\dfrac{\rm m}{\rm s}

\cos\theta=-\dfrac57

\theta=\cos^{-1}\left(-\dfrac57\right)\text{ OR }\theta=360^\circ-\cos^{-1}\left(-\dfrac57\right)

or approximately 136º or 224º.

Only one of these directions must be correct. Choosing between them is a matter of picking the one that satisfies <em>both</em> equations. We want

\left(7.0\dfrac{\rm m}{\rm s}\right)\sin\theta=-v

which means <em>θ</em> must be between 180º and 360º (since angles in this range have negative sine).

So the ducks must fly (relative to the air) in a direction 224º relative to the positive horizontal direction, or about 44º South of West.

8 0
3 years ago
A 29.0-kg block is initially at rest on a horizontal surface. A horizontal force of 71.0 N is required to set the block in motio
Julli [10]

Answer:

(a) \mu_s=0.25

(b) \mu_k=0.20

Explanation:

According to Newton's second law:

\sum F_y:N=mg\\\sum F_x:F_a=F_f

Recall that the frictional force is related jointly with the coefficient of friction and normal force F_f=\mu N. Replacing in the above equation, we get the coefficient of friction:

F_a=\mu N=\mu mg\\\mu=\frac{F_a}{mg}

(a) The  coefficient of static friction is related with the force required to set the block in motion:

\mu_s=\frac{71N}{29kg*9.8\frac{m}{s^2}}\\\mu_s=0.25

(b) The  coefficient of kinetic friction is related with the force required to keep the block moving with constant speed:

\mu_k=\frac{56N}{29kg*9.8\frac{m}{s^2}}\\\mu_k=0.20

3 0
3 years ago
Calculate the amount of work done if you use a 100N force to push a 50kg box 5m across the kitchen floor.
irinina [24]
So if the formula for work is force times displacement times cosine(theta), you'd plug in the numbers

100x5 (since there's no angle in the problem, cosine(theta) isn't used

100x5 = 500

So the answer would be B.

Hope that helps!
6 0
3 years ago
Read 2 more answers
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