With these questions, drawing it out would always help, the answer for this would be 90m if you add them all up. If it’s displacement, it would be 30m. But since it’s asking for the distance TRAVELED then it’s 90m
ANSWER: 90m
Thus, a swinging pendulum has its greatest kinetic energy and least potential energy in the vertical position, in which its speed is greatest and its height least; it has its least kinetic energy and greatest potential energy at the extremities of its swing, in which its speed is zero and its height is greatest.
Answer:
0.2631 N/C
Explanation:
Given that:
The radius of the wire r = 0.22 mm = 0.22 × 10⁻³ m
The radius of the thick wire r' = 0.55 mm = 0.55 × 10⁻³ m
The numbers of electrons passing through B, N = 6.0 × 10¹⁸ electrons
Electron mobility μ = 6.0 x 10-4 (m/s)/(N/C)
= 0.0006
The number of electron flow per second is calculated as follows:




The magnitude of the electric field is:
E = 
E = 
E = 
E = 0.2631 N/C