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kramer
3 years ago
6

Light passes from a material with index of refraction 1.25 to one with index of refraction 1.72. The angle of incidence is 34.3°

. What is the angle of refraction?
Physics
1 answer:
kicyunya [14]3 years ago
8 0

Answer:

angle of refraction is 24.17°

Explanation:

given data

index of refraction n1 =  1.25

index of refraction n2 = 1.72

angle of incidence θ1 =  34.3°

to find out

angle of refraction (θ2)

solution

we will apply here snells law that is

n1 sinθ1 = n2 sinθ2    .........................1

here put all these value and find θ2

1.25 sin34.3 = 1.72 sinθ2  

sinθ2  = 0.70440 /1.72

sinθ2 = 0.4095

θ2 = 24.17°

so here angle of refraction is 24.17°

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Identify the physical mechanism that causes turbulent thermal conductivity.
myrzilka [38]

Answer:

Option A is correct.

Eddies due to enhanced mixing of fluid

Explanation:

Turbulent thermal conductivity is thermal conductivity that arises from the turbulent flow of fluids. It comes into play when a particukar fluid moves into turbulent regiom of flow where flow is no longer orderly and streamlines aren't discernable with the fluid layers all warping into one another forming vortices.

It is represented as K and is shown mathematically through the heat flux at turbulent flow

q = vCρT' = - K (∂T/∂y)

where

K = turbulent thermal conductivity

T' = the eddy temperature relative to the mean value,

C = Heat capacity the fluid

q = the rate of thermal energy transport by turbulent eddies.

The physical mechanism that cause turbulent thermal conductivity are similar to the causes of turbulent flow of fluids.

This includes sharp changes in fluid pressure and velocity of flow which is evident in eddies that come about in the enhanced mixing of fluids.

Hope this Helps!!!

5 0
3 years ago
Can someone help me please
makvit [3.9K]

Answer:

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3 0
3 years ago
A certain atom has atomic number Z = 25 and atomic mass number A = 52. a. What is the approximate radius of the nucleus of this
wlad13 [49]

Answer:

a)The approximate radius of the nucleus of this atom is 4.656 fermi.

b) The electrostatic force of repulsion between two protons on opposite sides of the diameter of the nucleus is 2.6527

Explanation:

r=r_o\times A^{\frac{1}{3}}

r_o=1.25 \times 10^{-15} m = Constant for all nuclei

r = Radius of the nucleus

A = Number of nucleons

a) Given atomic number of an element = 25

Atomic mass or nucleon number = 52

r=1.25 \times 10^{-15} m\times (52)^{\frac{1}{3}}

r=4.6656\times 10^{-15} m=4.6656 fm

The approximate radius of the nucleus of this atom is 4.656 fermi.

b) F=k\times \frac{q_1q_2}{a^2}

k=9\times 10^9 N m^2/C^2 = Coulombs constant

q_1,q_2 = charges kept at distance 'a' from each other

F = electrostatic force between charges

q_1=+1.602\times 10^{-19} C

q_2=+1.602\times 10^{-19} C

Force of repulsion between two protons on opposite sides of the diameter

a=2\times r=2\times 4.6656\times 10^{-15} m=9.3312\times 10^{-15} m

F=9\times 10^9 N m^2/C^2\times \frac{(+1.602\times 10^{-19} C)\times (+1.602\times 10^{-19} C)}{(9.3312\times 10^{-15} m)^2}

F=2.6527 N

The electrostatic force of repulsion between two protons on opposite sides of the diameter of the nucleus is 2.6527

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