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2 years ago

What trend in ionization do you see going up and down?

1 answer:

5 0

Depending if you were going up, you would be seeing an increase in relative ionization energies in a particular group on the periodic table, and vice versa, if you go down the group, an decrease in the relative ionization energies.

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Why is the cell membrane essential for cell homeostasis?

Nadya [2.5K]

Hello,

Here is your answer:

The proper answer to this question is option C "To allow waste to exit the cell"! The cell membrane controls the matieral that goes in and out of the cell!

Your answer is C.

If you need anymore help feel free to ask me!

Hope this helps!

3 0

2 years ago

Read 2 more answers

Draw the two chair conformations of cis 1 chloro 2 methylcyclohexane

Mrrafil [7]

In chair conformations of cyclohexane, Cl group is on the first C and methyl group is on the second C. In the cis conformation both groups should be in the same orientation, either both side chains should be up and up or down and down. In this figure its up and up.
2 figures are drawn as when the chair conformation flips, the axial groups become equatorial and equatorial groups become axial. But they remain as up or down .
When A flips to B, Cl goes from axial to equatorial and CH3 goes from equatorial to axial but both remain up.

6 0

2 years ago

A 25.0 mL sample of 0.25 M potassium carbonate (K2CO3) solution is added to 30.0 mL of a 0.40 M barium nitrate (Ba(NO3)2) soluti

ozzi

Answer:

0.10M of Ba²⁺ is the concentration of the metal in excess

Explanation:

Based on the chemical reaction:

K₂CO₃(aq) + Ba(NO₃)₂(aq) → BaCO₃(s) + 2KNO₃(aq)

<em>1 mole of potassium carbonate reacts per mole of barium nitrate</em>

<em />

To solve this question we need to find the moles of each salt to find then the moles of Barium in excess:

<em>Moles K₂CO₃:</em>

0.025L * (0.25mol / L) = 0.00625moles K₂CO₃ = moles CO₃²⁻

<em>Moles Ba(NO₃)₂:</em>

0.030L * (0.40mol/L) = 0.012 moles of Ba(NO₃)₂ = 0.012 moles of Ba²⁺

That means moles of Ba²⁺ that don't react are:

0.012 mol - 0.00625mol = 0.00575 moles Ba²⁺

In 25 + 30mL = 55mL:

0.00575 moles Ba²⁺ / 0.055L =

<h3>0.10M of Ba²⁺ is the concentration of the metal in excess</h3>

4 0

2 years ago

Why isn't pure iron suitable for a replacement hip joint

Furkat [3]

<span>Because iron is an element meaning that it only contains iron atoms, pure iron is easily oxidized meaning that oxygen readily reacts with the surface of the iron which causes it to rust. Therefore, since the iron joint replacement is surrounded by wet tissues would it would rust and flake off which could cause serious problems. </span>

3 0

2 years ago

In some regions of the southwest United States, the water is very hard. For example, in Las Cruces, New Mexico, the tap water co

myrzilka [38]

Answer:

a) $46.734L$ of hard water is require to produce $45L$ of pure water.

b) Same water would not work for purifying sea water as it would require so much of energy.

Explanation:

Osmotic pressure of a solution is calculated by the formula,

Π= $iMRT$

Where,

Π is the osmotic pressure

$i$ is van't hoff factor

$M$ is molar concentration (mol/L)

$R$ is gas constant

$T$ is Temperature in Kelvin

Now,

$MgCO_{3}\rightarrow Mg^{2+}+ CO_{3}^{2-}$

So, according to the above equation $i=2$

Calculation concentration at which reverse osmosis will stop

$M=\frac{ Π }{iRT}$

$M=\frac{8atm}{2\times0.082L atm mol^{-1}K^{-1} \times 300K} \\M= 0.162M$

Calculating Initial concentration that is moles of $MgCO_{3}$

$n=\frac{given mass}{molar mass} \\\\n=\frac{560 \times 10^{-6}g}{84.32g/mol}\\\\N=6.642\times10^{-6}moles$

Calculating molarity

$M= 6.642 \times 10^{-6}\times 10{^3}\\M=6.642\times10^{-3}M$

Total number of moles in total volume must remain the same,

$C_{1}V_{1}=C_{2}V_{2}$

$0.006642M \times V_{1}=0.162M \times V_{2}$

$\frac{V_{1}}{V_{2}}= \frac{0.162}{0.006.642}=25.953$

$V_{1}=25.953 V_{2}$

Also, $V_{1}=45L$

$V_{2}=\frac{45}{25.953}\\ V_{2}= 1.734L$

So, net Volume,

$V=45L+1.734L=46.734L$

So, $46.734L$ is require to produce $45L$ of pure water.

Using the equation for $0.60M NaCl$ as well,

$C_{1}V_{1}=C_{2}V_{2}$

$C_{1}=0.60M\\V_{1}=45L\\C_{2}=0.162M\\V_{2}=?$

$V_{2}=\frac{0.60 \times 45}{0.167}\\V_{2}= 166.66L$

$Net water=166.66+45L=211.66L$

So, the same water would not work for purifying sea water as it would require so much of energy, as we require 211.66L of water to produce 45L of water.

7 0

2 years ago