Let us find the co ordinates of each vertex of the triangle .
Vertex A ( in firs second quadrant) = ( -5 ,3)
vertex B in third quadrant = ( -5, -5)
vertex C in fourth quadrant = ( 4, -2)
let us use distance formula AB^2 = ( -5 - 3)^2 + (-5 - -5 )^2 = 64 + 0
AB= 8
BC^2 = ( -2 - -5 )^2 + ( 4 - - 5)^2 = 9 + 81 = 90
BC = 9.48
AC^2 = ( -2 -3)^2 +( 4- -5)^2 = 25 + 81 = 106
AC= 10.29
Perimeter = sum of length of AB+ BC+ Ac = 8 + 10.29 + 9.48= 22.77
97 to 100, or 97 percent
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Answer:
Switch x and y.
Solve for x.
Function can be written as x²+4.
and last one will be 4.
;-)
Step-by-step explanation:
Answer:
80 men
Step-by-step explanation:
4 : 5 10 : 9
40 : 50 : 45
40 x 2 = 80
Answer:
27
x^(
6
)y^(
9)
Step-by-step explanation:
