Question

what mass of silver chloride can be produced from 1.11 l of a 0.156 m solution of silver nitrate? express your answer with the appropriate units.

Answer 1

The mass of silver chloride produced is 24.79g.

Given,

volume = 1.11 L

Molarity = 0.156 M

First, convert molarity to moles by multiplying by the volume:

0.156 M AgNO3 = (0.156 moles AgNO3)/1 L x 1.11 L = 0.173 moles AgNO3

We are only interested in AgCl, not AgNO3. We convert moles of silver nitrate to moles of silver chloride using the balanced equation. This is a 1:1 conversion:

0.173 moles AgNO3 x (1 mole AgCl)/(1 mole AgNO3) = 0.173 moles AgCl

To get mass from moles, we multiply by the molar mass:

0.173 moles AgCl x (143.32 g/mol) =  24.79 g AgCl

To know more about molarity visit the link:

brainly.com/question/8732513?referrer=searchResults

#SPJ4