The mass of silver chloride produced is 24.79g.
Given,
volume = 1.11 L
Molarity = 0.156 M
First, convert molarity to moles by multiplying by the volume:
0.156 M AgNO3 = (0.156 moles AgNO3)/1 L x 1.11 L = 0.173 moles AgNO3
We are only interested in AgCl, not AgNO3. We convert moles of silver nitrate to moles of silver chloride using the balanced equation. This is a 1:1 conversion:
0.173 moles AgNO3 x (1 mole AgCl)/(1 mole AgNO3) = 0.173 moles AgCl
To get mass from moles, we multiply by the molar mass:
0.173 moles AgCl x (143.32 g/mol) = 24.79 g AgCl
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