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BigorU [14]
1 year ago
15

what mass of silver chloride can be produced from 1.11 l of a 0.156 m solution of silver nitrate? express your answer with the a

ppropriate units.
Chemistry
1 answer:
tangare [24]1 year ago
8 0

The mass of silver chloride produced is 24.79g.

Given,

volume = 1.11 L

Molarity = 0.156 M

First, convert molarity to moles by multiplying by the volume:

0.156 M AgNO3 = (0.156 moles AgNO3)/1 L x 1.11 L = 0.173 moles AgNO3

We are only interested in AgCl, not AgNO3. We convert moles of silver nitrate to moles of silver chloride using the balanced equation. This is a 1:1 conversion:

0.173 moles AgNO3 x (1 mole AgCl)/(1 mole AgNO3) = 0.173 moles AgCl

To get mass from moles, we multiply by the molar mass:

0.173 moles AgCl x (143.32 g/mol) =  24.79 g AgCl

To know more about molarity visit the link:

brainly.com/question/8732513?referrer=searchResults

#SPJ4

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Answer: The volume of 0.640 grams of O_{2} gas at Standard Temperature and Pressure (STP) is 0.449 L.

Explanation:

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As number of moles is the mass of substance divided by its molar mass.

So, moles of O_{2} (molar mass = 32.0 g/mol) is as follows.

No. of moles = \frac{mass}{molar mass}\\= \frac{0.640 g}{32.0 g/mol}\\= 0.02 mol

Now, ideal gas equation is used to calculate the volume as follows.

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T = temperature

Substitute the values into above formula as follows.

PV = nRT\\1.0 atm \times V = 0.02 mol \times 0.0821 L atm/mol K \times 273 K\\V = 0.449 L

Thus, we can conclude that the volume of 0.640 grams of O_{2} gas at Standard Temperature and Pressure (STP) is 0.449 L.

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A chef is cooking with a 2000-gram stainless steel skillet. Stainless steel has a specific heat capacity of 0.450 J/(g *oC). How
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Answer:

Q = 90,000 J

Explanation:

Given data:

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Formula:

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Q = amount of heat absorbed or released

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