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ira [324]
3 years ago
7

Boyle's law deals what quantities?

Chemistry
2 answers:
irga5000 [103]3 years ago
5 0
The answer is pressure and volume because they are both proportional to one another.
kirill115 [55]3 years ago
4 0
Boyle's law<span> declares that the force and volume of a propellant are mannerly proportionate to each. </span>
You might be interested in
How many Moles of NAOH are present in 2.50L of 0.300 M NaOH?
maw [93]
<h3>Answer:</h3>

0.75 moles NaOH

<h3>Explanation:</h3>

We are given;

Volume of NaOH solution = 2.5 Liters

Molarity of NaOH = 0.300 M

We are required to calculate the moles of NaOH

We need to establish the relationship between moles, molarity and volume of a solution.

That would be;

Concentration/molarity = Moles ÷ Volume

Therefore;

Moles = Concentration × Volume

Thus;

Moles of NaOH = 0.300 moles × 2.50 L

                         = 0.75 moles

Therefore, the number of moles of NaOH is 0.75 moles

8 0
3 years ago
All BUT one factor contributes to natural selection. That factor is
Juli2301 [7.4K]
<span>the one that is not a factor that contribute to natural selection is : Population stability population refer to the capability of a community to maintain its total amount of organisms within a specific period of time. This has nothing to do with natural selection, which basically a nature's way to reduce the number of organism to findout which organisms are more adaptive</span>
7 0
3 years ago
Read 2 more answers
Read the chemical equation. Fe2O3 + CO → Fe + CO2 If 2 moles of Fe2O3 react with 9 moles of CO, how many moles of each product a
cluponka [151]

Answer:

4 moles Fe and 6 moles CO2 are the moles of each products formed

Explanation:

Fe2O3 + 3CO → 2Fe + 3CO2

1st step Ballance the equation. Afterwards, you can work properly

1 mol of Fe2O3 reacts with 3 moles of CO to make 2 moles of Fe and 3 moles of CO2

2nd step Predict the reactant in excess and limitant reagent.

If 1 moles of Fe2O3 reacts with 3 moles of CO

2 moles of Fe2O3 reacts with 6 moles of CO     (2.3) /1

I have 9 moles of CO, so the Fe2O3 is my limitant reagent.

<u><em>REMEMBER</em></u> you always have to work with the limitant.

If 3 moles of CO reacts with 1 mol of Fe2O3

9 moles of CO reacts with 3 moles of Fe2O3     (9.1) /3

I have 2 moles of Fe2O3, so I still have Fe2O3, by the way the CO is the reactant in excess. (Just to show all)

3rd step Work with the limitant reagent.

1 mol of Fe2O3 ___ makes____ 2 moles of Fe  +  3 moles of CO

2 mol of Fe2O3 ___ makes ___ 4 moles of Fe  +  6 moles of CO

5 0
2 years ago
Predict what will be observed in each experiment below. experiment predicted observation.
irga5000 [103]

Answer:

The correct answer is -

1.  a) The bubbles will shrink, some may vanish.

2. a) Can A will make a louder and stronger fizz than can B.

Explanation:

In the first question, it is given that the bottle is not opened and therefore, squeezing the bottle filled with a carbonated drink will increase the pressure on the carbonated liquid which forces the bubbles to dissolve or displace or vanish as it moves to empty space.

Thus, the correct answer would be - The bubbles will shrink, some may vanish

In the second question, there are two different conditions for two different unopened cans of carbonated water that are different temperatures one at the garage with higher temperature and one in the fridge at low temperature. As it is known that higher the temperature less will be solubility of gas in liquid so gas in can A will be less soluble which means it has more gas and it will make louder and stronger fizz than B which was stored at low temperature.

thus, the correct answer would be - Can A will make a louder and stronger fizz than can B.

8 0
2 years ago
a sealed container filled with argon gas at 35 c has a pressure of 832 torr. if the volume of the container is decreased by a fa
lesya692 [45]

Answer:

If the volume of the container is decreased by a factor of 2 the pressure is is increased by the same factor to 1664 torr.

Explanation:

Here we have Boyle's law which states that, at constant temperature, the volume of a given mass of gas is inversely proportional to its pressure

V ∝ 1/P or V₁·P₁ = V₂·P₂

Where:

V₁ = Initial volume

V₂ = Final volume = V₁/2

P₁ = Initial pressure = 832 torr

P₂ = Final pressure  = Required

From V₁·P₁ = V₂·P₂ we have,

P₂ = V₁·P₁/V₂ = V₁·P₁/(V₁/2)

P₂  = 2·V₁·P₁/V₁ = 2·P₁ = 2× 832 torr = 1664 torr

6 0
3 years ago
Read 2 more answers
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