Answer:
8.33mol/L
Explanation:
First, let us calculate the molar mass of of formaldehyde (CH2O). This is illustrated below:
Molar Mass of CH2O = 12 + (2x1) + 16 = 12 + 2 + 16 = 30g/mol
Mass of CH2O from the question = 0.25g
Number of mole CH2O =?
Number of mole = Mass /Molar Mass
Number of mole of CH2O = 0.25/30 = 8.33x10^-3mole
Now we can calculate the molarity of formaldehyde (CH2O) as follow:
Number of mole of CH2O = 8.33x10^-3mole
Volume = 1mL
Converting 1mL to L, we have:
1000mL = 1L
Therefore 1mL = 1/1000 = 1x10^-3L
Molarity =?
Molarity = mole /Volume
Molarity = 8.33x10^-3mole/1x10^-3L
Molarity = 8.33mol/L
Therefore, the molarity of formaldehyde (CH2O) is 8.33mol/L
Sodium hypochlorite is used in iodoform test for the oxidation of alcohol to aldehyde as shown in the image attached:
Here sodium hypochlorite is formed by the reaction of NaOH with I2 that further oxides alcohols to aldehydes.
Group of tissues form a cell , and a group of cells form an organ
A is is a double replacement reaction (Cations and anions switch)
B is a Decomposition reaction (Breaks down into simpler substances)
C is a Synthesis or Combination reaction (both are the same thing)
D is a Combustion reaction (compound made of carbon and hydrogen reacts with oxygen)
and E is a Single replacement reaction (Cations trade)
Hope this helps! :)
