The correct matches are as follows:
<span>1. Na+ + Cl- → NaCl
</span>D. synthesis reaction<span>
2. CCl4 → C + 2Cl2
</span>A. decomposition reaction<span>
3. H+Cl- + Na+OH- → Na+Cl- + H2O
</span>B. exchange reaction<span>
4. ADP + P + E ATP
</span><span>C. reversible reaction
</span>
Hope this answers the question. Have a nice day.
Explanation:
protons.
An acid can also be thought of as a chemical that can neutralize a base. Similarly, a base can neutralize an acid.
Acids turn litmus paper red, while bases make litmus paper turn blue.
Some examples of acids are sulfuric acid, hydrochloric acid, nitric acid, and so on. Some examples of bases are sodium hydroxide, potassium hydroxide, and so on.
Acids generally taste sour, while bases have a bitter taste.
Alkalis are the bases that are water-soluble, which means that they dissolve in water. In other words, not all bases are water-soluble, and only the water-soluble bases are known as alkalis. An example of an alkali is sodium hydroxide. It is a base because it can neutralize an acid, and because it is water-soluble, it is an alkali. An example of a base that is not alkali is copper oxide. This chemical can neutralize an acid, but it is insoluble in water.
In other words, all alkali are bases but not all bases are alkalis.
Also, an alkali has a hydroxide group, while a base has an oxide group in it.
Answer:
There will be very little of BrOCl BrCl
Explanation:
Based on the equilibrium:
Br2(g) + OCl2(g) ⇄ BrOCl(g) + BrCl(g)
The equilibrium constant, Kc, is:
Kc = 1.58x10⁻⁵ = [BrOCl] [BrCl] / [Br2] [OCl2]
As Kc is <<< 1, in equilibrium, the concentration of products will remain lower regard to the concentration of the reactants. That means, right answer is;
<h3>There will be very little of BrOCl BrCl</h3>
Answer is: amount of sugar in milk chocolade is 3333 mg.
To solve this question, make proportion: if 12,00 grams of milk chocolate contain 8,00 grams of sugar, than 5,00 grams contain:
12,000 g : 8,000 g = 5,000 g : m(sugar).
12,000 g · m(sugar) = 8,000 g · 5,000 g.
m(sugar) = 40,000 ÷ 12,000.
m(sugar) = 3,333 g = 3333 mg.
