0.000132 g of hydrated sodium borate (Na₂B₄O₇ · 10 H₂O)
Explanation:
First we need to find the number of moles of sodium borate (Na₂B₄O₇) in the solution:
molar concentration = number of moles / volume (L)
number of moles = molar concentration × volume (L)
number of moles of Na₂B₄O₇ = 0.1 × 0.5 = 0.05 moles
We know now that we need 0.05 moles of hydrated sodium borate (Na₂B₄O₇ · 10 H₂O) to make the solution.
Now to find the mass of hydrated sodium borate we use the following formula:
number of moles = mass / molar weight
mass = number of moles × molar weight
mass of hydrated sodium borate = 0.05 / 381 = 0.000132 g
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molar concentration
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Explanation:
Assuming that moles of nitrogen present are 0.227 and moles of hydrogen are 0.681. And, initially there are 0.908 moles of gas particles.
This means that, for 
moles of 
+ moles of 
= 0.908 mol
Since, 2 moles of = 
= 0.454 mol
As it is known that the ideal gas equation is PV = nRT
And, as the temperature and volume were kept constant, so we can write
= 
= 
= 
= 5.2 atm
Therefore, we can conclude that the expected pressure after the reaction was completed is 5.2 atm.
Paramecia are examples of unicellular organisms. They are protists.
<h3>Protists</h3>
Protists are eukaryotic unicellular (single-celled) organisms that do not fit into any other category.
Paramecia are protists microorganisms generally found in aquatic habitats (e.g., a pond).
Paramecia generally have an oblong shape and they are covered with tiny structures known as cilia (for motion).
Learn more about protists here:
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First, we are discussing reversible reactions here, since the reaction is proceeded in both directions forming both reactants and products.
The reaction is symbolized as:
A + B <.........> C + D
The first given is:
The rate of appearance of D is twice the disappearance of A
This means that the coefficient of D in the reaction is twice the coefficient of A
The second given is:
The rate of appearance of D is one third the disappearance of B.
This means that the coefficient of D in the reaction is 1/3 that of B. This also means that the coefficient of B is 3 times that of D.
Combining these two pieces of information, we will find that the best equation that resembles this scenario is:
<span>A + 6 B <.........> C + 2 D </span>
There will be 89.865 grams of Ar. If you put it in sig figs, it will be rounded to 89.9g At.
