50 PoInts for math homework Waxton

The difference between a number c and 13 is −2. <br><br> Equation: <br><br> Solution:

Taya2010 [7]

Answer:

c - 13 = - 2

grouping of like terms

c = -2 + 13

c = 11

4 0

2 years ago

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6. 2(x + 6) = 3(x + 1)

diamong [38]

Answer:

x=9

Step-by-step explanation:

2(x + 6) = 3(x + 1)

2x+12=3x+3

2x+12-12=3x+3-12

2x=3x-9

2x-3x=-9

-1x=-9

-1x÷-1=-9÷-1

x=9

7 0

3 years ago

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Hector has $590 in his account. He earned $15 per hour for x hours. Jeremy has $545 in his account. He earned $20 per hour for x

Nutka1998 [239]

Answer:

equation = 590 + 15x = 545 + 20x

No. of hours worked = 9

Step-by-step explanation:

Given that both worked for same number of hours

and

Jeremy worked for for x hours

it meant that Hector also worked for x hours(it is also mentioned same in the problem)

now that we know the number of hours worked in form of x

lets find

total money in their account if they worked for x hours

___________________________________________

For Hector

Money in Hector's account = $590

Earning for Hector in 1 hour = $15

Earning for Hector in x hour = x*Earning for Hector in 1 hour = $15x

Total money in with Hector after x hours of work

= Money in Hector's account + Earning for Hector in x hour = $590 + $15x

Similarly

For Jeremy

Money in Jeremys account = $545

Earning for Jeremy in 1 hour = $20

Earning for Jeremy in x hour = x*Earning for Jeremy in 1 hour = $20x

Total money in with Jeremy after x hours of work

= Money in Jeremy's account + Earning for Jeremy in x hour = $545 + $20x

Given that they same amount of money

thus

$590 + $15x = $545 + $20x

$sign gets cancelled from both sides

590 + 15x = 545 + 20x Thus, we got the required equation

=> 590 - 545 = 20x - 15x

=> 45 = 5x

=> x = 45/5 = 9

Thus, both of them worked for 9 hours

6 0

3 years ago

What is the answers of 6b and 6c?

Dimas [21]

Hello,

6b) (i) As you can see, in the first year the price drops from 27,000 to 17,000. (Look at year 0-1 on the x axis). To find the percentage drop, find the difference between the two values and divide it over the initial value of 27,000.

So, the percentage drop in the first year is:
(27000-17000) / (27000) = 0.37, or a 37% drop

The answer is 37%.

(ii) For this question, we basically have the same process as the previous question except for the second year.

From year 1 to year 2, the value starts at 17,000 and ends at 15,000.
To find the percentage drop, we do:
(17000 - 15000) / (17000) = 0.118 ≈ 0.12, or a 12% drop

The answer is 12%.

6c) To find the percentage depreciation over the first 5 years, we look at the initial value (x = 0) and the value after 5 years (x = 5), and use these values in the same percentage formula we have been using.

The initial value of the car is 27,000, and after 5 years the value is 8,000.
This is a percentage drop of (27000 - 8000) / (27000) = 0.70, or a 70% drop.

The answer is 70%.

Hope this helps!

7 0

3 years ago

Suppose that grade point averages of undergraduate students at one university have a bell-shaped distribution with a mean of 2.5

iris [78.8K]

Answer:

By the Empirical Rule, 99.7% of the students have grade point averages that are between 1.28 and 3.8.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed(bell-shaped) random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 2.54

Standard deviation = 0.42.

Between 1.28 and 3.8?

1.28 = 2.54 - 3*0.42

So 1.28 is 3 standard deviations below the mean

3.8 = 2.54 + 3*0.42

So 3.8 is 3 standard deviations above the mean

By the Empirical Rule, 99.7% of the students have grade point averages that are between 1.28 and 3.8.

5 0

2 years ago

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