Answer:
14.7838
Explanation:
Given that;
A student uses a solution that contains 16 g of water to conduct an experiment and at the end of an hour ; the amount have decreased by 3.5%
The mathematically illustration for this is given as
= 16 g × 3.5%
= 
= 0.56
After an hour; the amount have decreased by 16 - 0.56
= 15.44
after 2 hours the water decreased by another 4.25%
i.e 
⇒ 0.6562
after two hours , the amount would have decreased by:
= 15.44 - 0.6562
= 14.7838
Li + H2O →<span> LiOH + H2
The equation is currently unbalanced, so to balance it out, you have to have the same number of each molecule on each side. It'll look like this:
</span>2Li + 2H2O → <span>2LiOH + H2
</span>
Also, in case you want to identify the phases as well, it'll be like this:
2Li (s) + 2H2O (l) → 2LiOH (aq) + H2 (g)
"s" is solid.
"l" is liquid.
"aq" is aquas.
"g" is gas.
Answer:
d. Transition metal
Explanation:
Copper is in transition metal block in periodic table.
An ion is an element that bears only one electric charge, either positive or negative. An isotope is an element with the same number of protons but a different number of neutrons. An electron is a negatively charged subatomic particle. A dipole fits the characteristics. Hence, the answer is B.
Answer:
Explanation:
Law of conservation of mass:
According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.
This law was given by french chemist Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.
For example:
In given photosynthesis reaction:
6CO₂ + 6H₂O + energy → C₆H₁₂O₆ + 6O₂
there are six carbon atoms, eighteen oxygen atoms and twelve hydrogen atoms on the both side of equation so this reaction followed the law of conservation of mass.
Law of multiple proportion:
When two elements combine to form two or more compounds with different proportions, the weight of on element that combine with other elements in fixed proportion is in the ratio of small whole number.
For example:
Consider the example of carbon dioxide and carbon monoxide.
CO and CO₂
we are given with 1 g carbon on both case while 1.3 g oxygen for carbon monoxide and 2.6 for carbon dioxide. It means the ratio of oxygen is 1:2.
There is 1.3 g of oxygen in carbon monoxide for one g of carbon while in case of carbon dioxide there is 2.6 g of oxygen for one gram of carbon.
