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Ivahew [28]
3 years ago
7

In which direction does the electric field point at a position directly east of positive charge.

Chemistry
1 answer:
butalik [34]3 years ago
4 0

Answer:

The direction of the field is taken to be the direction of the force it would exert on a positive test charge. The electric field is radially outward from a positive charge and radially in toward a negative point charge.

Explanation:

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Compute 6.28×1013+7.30×1011.
Simora [160]
6.28×1013+7.30×1011 this =13741.94
6 0
3 years ago
The absolute temperature of a gas is increased four times while maintaining a constant volume. What happens
poizon [28]

Answer:

<u>It increases by a factor of four</u>

Explanation:

Boyle's Law : At constant temperature , the volume of fixed mass of a gas is inversely proportional to its pressure.

pV = K.......(1)

pV = constant

Charles law : The volume of the gas is directly proportional to temperature at constant pressure.

V = KT

or V/T = K = constant ....(2)

Applying equation (1) and (2)

\frac{PV}{T}=K

\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}

According to question ,

T2 = 4 (T1)

V2 = V1

Put the value of T2 and V2 , The P2 can be calculated,

\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{1}}{4T_{1}}

V1 and V1 cancel each other

T1 and T1 cancel each other

We get,

P1=\frac{P2}{4}

or

P2 = 4 P1

So pressure increased by the factor of four

5 0
3 years ago
1. Show the mechanism for the main product for the monochlorination of 2-methylbutane. List all other products.
Bad White [126]

Answer:

See explanation below

Explanation:

First, we need to understand that the monochlorination of an alkane like this one, involves substitution of one of the atoms of hydrogen of the molecule for an atom of chlorine.

This reaction takes place when the alkane reacts with Cl₂ in presence of light or heat.

When this happens, the first step involves the breaking of the double bond of the chlorine to form the ion Cl⁻.

The next step involves the substraction of the hydrogen of the molecule by the Chlorine. This will leave the alkane with a lone pair available for reaction.

The third step, the alkane with the lone pair of electron substract a chlorine for the beggining and form the mono chlorinated product.

The final step involves forming the remaining products with the remaining reagents there.

In the picture attached you have the mechanism and product for this reaction:

3 0
3 years ago
Read 2 more answers
EXPLAIN how to identify the reducing agent in a reaction of magnesium with oxygen
Alina [70]

Explanation:

Mg+O>MgO

Here the mg loses it electron and is oxidised and oxygen gains and is reduced.

Mg(2+)and O(2-)

Mg is a reducing agent it makes oxygen to be reduced while itself being oxidised and vice versa.

8 0
3 years ago
When you add up all the kinetic energy and potential energy of a substance you are finding its _________________.
Aleks [24]

a ) temperature

hope this helps

8 0
3 years ago
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