Most acidic: solution B, pH = 1
Most Basic: solution C, pH = 13
Least acidic: solution A, pOH = 1
Explanation:
so moles = mass ÷ mr (1+ 79.9)
so 10.00g ÷ 80.9
which is 0.1236093943
so to 3 S.F is 0.124 moles
also there is 1 to 1 ratio for LiOH to HBr
hope this helps :)
The heat required to vaporize 43.9 g of acetone at its boiling point is calculated as below
the heat of vaporization of acetone at its boiling point is 29.1 kj/mole
find the moles of acetone = mass/molar mass
= 43.9g /58 g/mol =0.757 moles
heat (Q) = moles x heat of vaporization
= 29.1 kj/mole x 0.757 moles = 22.03 kj
