<u>Answer:</u> The mole fraction of oxygen gas is 0.479
<u>Explanation:</u>
We are given:
Partial pressure of methane = 143 mmHg
Partial pressure of nitrogen gas = 469 mmHg
Partial pressure of oxygen gas = 563 mmHg
Total pressure = (143 + 469 + 563) = 1175 mmHg
To calculate the mole fraction of oxygen gas, we use the equation given by Raoult's law, which is:
where,
= partial pressure of oxygen gas = 563 mmHg
= total pressure = 1175 mmHg
= mole fraction of oxygen gas = ?
Putting values in above equation, we get:
Hence, the mole fraction of oxygen gas is 0.479
There will be 5 electron shells that will be filled
Answer:
C₆H₈O₆
Explanation:
First off, the<u> percent of oxygen by mass</u> of vitamin C is:
- 100 - (40.9+4.58) = 54.52 %
<em>Assume we have one mol of vitamin C</em>. Then we would have <em>180 grams</em>, of which:
- 180 * 40.9/100 = 73.62 grams are of Carbon
- 180 * 4.58/100 = 8.224 grams are of Hydrogen
- 180 * 54.52/100 = 98.136 grams are of Oxygen
Now we <u>convert each of those masses to moles</u>, using the <em>elements' respective atomic mass</em>:
- C ⇒ 73.62 g ÷ 12 g/mol = 6.135 mol C ≅ 6 mol C
- H ⇒ 8.224 g ÷ 1 g/mol = 8.224 mol H ≅ 8 mol H
- O ⇒ 98.136 g ÷ 16 g/mol = 6.134 mol O ≅ 6 mol O
So the molecular formula for vitamin C is C₆H₈O₆
Br- < Se2- < As3- < Sr2+ < Rb+
I hope this helps although I'm not a hundred percent sure!