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10 months ago

If sodium is burned in chlorine gas, a compound is formed that dissolves in water. What colour will the solution be?

1 answer:

6 0

If sodium is burned in chlorine fuel, a compound is formed that dissolves in water. the solution be: Bright yellow mild

Chlorine is a yellow-green gas at room temperature. Chlorine has a smelly, annoying scent similar to bleach that is detectable at low concentrations. The density of chlorine gasoline is about 2.5 times extra than air, so one can reason it to initially stay near the floor in regions with little air movement.

Chlorine gasoline can be recognized by using its smelly, anxious smell, which is like the scent of bleach. The sturdy scent may additionally provide a good enough caution to human beings that they have been uncovered. Chlorine fuel appears to be yellow-green in color. Concentrations of approximately 400 ppm and past are commonly fatal over a half-hour, and at 1,000 ppm and above, fatality ensues within only some mins. A spectrum of scientific findings can be present in those uncovered to excessive tiers of chlorine.

Learn more about Chlorine here:

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in a certain solvent is first order with respect to (CH3)3CBr and zero order with respect to OH2. In several experiments the rat

Inga [223]

Answer:

Ea= -175.45J

A= 3.5×10^14

k=3.64 ×10^14 s^2.

Explanation:

From

ln k= -(Ea/R) (1/T) + ln A

This is similar to the equation of a straight line:

y= mx + c

Where m= -(Ea/R)

c= ln A

y= ln k

Therefore

21.10 3 104= -(Ea/8.314)

Ea=-( 21.10 3 104×8.314)

Ea= -175.45J

b) ln A= 33.5

A= e^33.5

A= 3.5×10^14

k= Ae^-Ea/RT

k= 3.5×10^14 × e^ -(-175.45/8.314×531)

k = 3.64 ×10^14 s^2.

8 0

3 years ago

What is the concentration of 60 mL of H3PO4 if it is neutralized by 225 mL of 2 M Ba(OH)2?

goldfiish [28.3K]

7.5 M is the concentration of 60 ml of H3PO4 if it is neutralized by 225 ml of 2 M Ba(OH)2.

Explanation:

Data given:

volume of phosphoric acid, Vacid =60 ml

volume of barium hydroxide, Vbase = 225 ml

molarity of barium hydroxide, Mbase = 2M

Molarity of phosphoric acid, Macid =?

the formula for titration is used as:

Macid x Vacid = Mbase x Vbase

rearranging the equation to get Macid

Macid = $\frac{Mbase x Vbase}{Vacid}$

Macid = $\frac{225 X 2}{60}$

Macid = 7.5 M

the concentration of the phosphoric acid is 7.5 M and the volume is 60 ml. Thus 7.5 M solution of phosphoric acid is used to neutralize the barium hydroxide solution of 2M.

8 0

3 years ago

Read 2 more answers

A reaction produces 74.10 g Ca(OH)2 after 56.08 g CaO is added to 36.04 g H2O. How should the difference in the masses of reacta

melomori [17]

Cao + H2O ---->Ca(OH)2
Calculate the number of each reactant and the moles of the product
that is
moles = mass/molar mass
The moles of CaO= 56.08g/ 56.08g/mol(molar mass of Cao)= 1mole
the moles of water= 36.04 g/18 g/mol= 2.002moles
The moles of Ca (OH)2=74.10g/74.093g/mol= 1mole

The mass of differences of reactant and product can be therefore
explained as
1 mole of Cao reacted completely with 1 mole H2O to produce 1 mole of Ca(OH)2. The mass of water was in excess while that of CaO was limited

3 0

3 years ago

BRAINLIESTTT ASAP!!!! PLEASE HELP ME :)

Elan Coil [88]

Answer:

1s² 2s²2p³

Explanation:

If the atom has seven electrons, it is Element 7 (nitrogen).

In the Periodic Table, you count the electrons in all the subshells up to

No. 7.

In the first Period, you have filled the 1s level (2 electrons).

In the second Period, you have filled the 2s subshell (2 electrons) and put three electrons in the 2p subshell.

Thus, the electron configuration is

1s² 2s²2p³

Note how the superscripts tell you the number of electrons in each subshell: <em>2 + 2 + 3 = 7</em>.

6 0

2 years ago

Draw it draw lewis dot structures for each hypothetical molecule shown below, using the correct number of valence electrons for

soldi70 [24.7K]

The first molecule is a sensible molecule having complete octet of each atom such as C, H and O whereas the second molecule having hydrogen present between the aldehyde and methyl group and thus showing hydrogen is making bond with aldehyde and methyl as well which is not possible because hydrogen only having one electron in its octet due to which it can only form a single bond by sharing its valence electron.

6 0

3 years ago