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BARSIC [14]
4 years ago
11

-

Physics
2 answers:
Otrada [13]4 years ago
7 0

The energy stored in a spring is

E = 1/2 (k x²)

' k ' is the spring constant . . . the number of newtons of force it takes to stretch or compress the spring by one meter from its relaxed length

' x ' is the distance the spring is stretched or compressed

For this problem, we know ' E ' and ' x ', and we need to find ' k '.

E = 1/2 (k x²)

1,000 = 1/2 (k) (0.025²)

1,000 = 1/2 (k) (0.000625)

Multiply each side by 2 :  

2,000 = (k) (0.000625)

Divide each side by 0.000625:

(2,000) / (0.000625) = k

k = 3,200,000

The spring constant is <em>3.2 x 10⁶ Newtons per meter .</em>

<em></em>

This is a very stiff spring !  My calculator says that if you want to stretch it just 1 inch, you have to pull it with a force of 18,285 pounds ! !  If such a spring exists, it might be used as part of the suspension for a tank or a concrete truck.

ziro4ka [17]4 years ago
6 0

Answer:

34

Explanation:

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A 49-year-old female was referred for mammography, but she is very apprehensive after reading about the risk of ionizing radiati
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4 0
4 years ago
An empty rubber balloon has a mass of 12.5 g. The balloon is filled with helium at a density of 0.181 kg/m3. At this density the
Eduardwww [97]

Answer: 1.14 N

Explanation :

As any body submerged in a fluid, it receives an upward force equal to the weight of the fluid removed by the body, which can be expressed as follows:

Fb = δair . Vb . g = 1.29 kg/m3 . 4/3 π (0.294)3  m3. 9.8 m/s2

Fb = 1.34 N

In the downward direction, we have 2 external forces acting upon the balloon: gravity and the tension in the line, which sum must be equal to the buoyant force, as the balloon is at rest.

We can get the gravity force as follows:

Fg = (mb +mhe) g  

The mass of helium can be calculated as the product of the density of the helium times the volume of the balloon (assumed to be a perfect sphere), as follows:

MHe = δHe . 4/3 π (0.294)3 m3 = 0.019 kg

Fg = (0.012 kg + 0.019 kg) . 9.8 m/s2 = 0.2 N

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6 0
3 years ago
I have a voltage source of 12V but a light that only burns at 5V. The lamp works on 18 mA. Calculate the resistance that you EXT
ratelena [41]

Answer:

The resistance that will provide this potential drop is 388.89 ohms.

Explanation:

Given;

Voltage source, E = 12 V

Voltage rating of the lamp, V = 5 V

Current through the lamp, I = 18 mA

Extra voltage or potential drop, IR =  E- V  

                                                    IR = 12 V - 5 V = 7 V

The resistance that will provide this potential drop (7 V) is calculated as follows:

IR = V

R = \frac{V}{I} = \frac{7 \ V}{18 \times 10^{-3} A} \ = 388.89 \ ohms

Therefore, the resistance that will provide this potential drop is 388.89 ohms.

7 0
3 years ago
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