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e-lub [12.9K]
3 years ago
10

I need help with finding the rest of the missing things..like the current (I), resistance, and voltage (v)

Physics
1 answer:
Finger [1]3 years ago
8 0
The total current is 1.5 A.
You know how much goes through the two bulbs.
The rest goes through the single bulb.

The single bulb is connected to the full battery voltage.

The resistance of the single bulb is V/I. (It turns out to be the same as the other 2 bulbs.)

The voltage across
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The 60 kg man in the bosun's chair exerts a pull of 363 n on the rope for a short interval. Find his acceleration in m/s2. Negle
LUCKY_DIMON [66]

The acceleration when a 60 kg man in bosun's chair exerts a pull, is -3.76 m/s².

<h3>What is acceleration?</h3>

The acceleration is the time rate of change of velocity.

Given the mass of man m= 60 kg and pull = 363N

According to the equilibrium conditions, 3T -mg =ma

The pull is equal to the tension 3T =363 N

Substituting the values, we get

363N - 60x 9.81 = 60a

a =-3.76m/s²

Thus, the acceleration is -3.76m/s².

Learn more about Acceleration.

brainly.com/question/12550364

#SPJ4

6 0
2 years ago
The speed of light in a solid is 1.24 x 108 m/s. <br> Calculate the index of refraction
Dahasolnce [82]

Answer:

125

Explanation:

7 0
3 years ago
Which part of the electromagnetic spectrum is nearest to radio waves?
svetlana [45]

The part of the electromagnetic spectrum closest to radio waves is <u> microwaves</u>.

The wavelength of radio waves ranges from 10 cm to more than 1 km. The part of the electromagnetic spectrum that occurs closest to the radio waves is called the microwave region.

Microwaves have wavelengths ranging from around 1 mm to 10 cm.

The waves overlap in the region of 10 cm.

Thus, the region of electromagnetic spectrum closest to radiowaves is <u> microwaves.</u>

3 0
3 years ago
Read 2 more answers
A clay ball (mass = 0.25kg) has a rightward momentum of +1.75 kg∙m/s. A second clay ball (mass = 0.25 kg) has a leftward momentu
julia-pushkina [17]

1)

\begin{gathered} E1=\frac{1}{2}m_1v_1^2+\frac{1}{2}m_1v_2^2 \\ where: \\ m_1=m_2=0.25kg \\ v_1=7m/s \\ v_2=-7m/s \\ so: \\ E1=\frac{1}{2}0.25(7^2)+\frac{1}{2}0.25(7^2) \\ E1=6.125+6.125 \\ E1=12.25J \end{gathered}

Answer:

d. 12.25J

------------------------

2)

According to the conservation of energy:

\begin{gathered} E1=E2 \\ so: \\ E2=12.25J \end{gathered}

Answer:

b. 12.25

-------------------------------

3)

P1=m_1v_2+m_2v_2=+1.75-1.75=0

Answer:

d. 0 kg∙m/s

-----------------------------------------

4)

Using conservation of momentum:

\begin{gathered} P1=P2 \\ so: \\ P2=0 \end{gathered}

Answer:

b. 0 kg•m/s

3 0
1 year ago
A marble is flicked off the edge of a table. The motion of the marble follows a parabolic path.
dem82 [27]

When marble is flicked off the edge of a table then the at the instant it will move off the table the velocity is horizontal while due to force of gravitation the marble will start accelerating downwards.

So here we will say that the velocity of marble will remain constant through out the motion in X direction as there is no force in that direction

While in Y direction the marble will have gravitational force due to which marble will accelerate downwards

So the path of the marble will be parabolic path

hence the correct answer will be

<em>A. </em>

<em>Only one continuous force is acting on the marble.</em>

5 0
4 years ago
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