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meriva
1 year ago
14

to a concentrated buffer of ph 9.0 was added an equal volume of an aqueous solution that was 0.20 m in each of the ions ca2 , cd

2 , and cu2 . the expected precipitate would consist of:
Chemistry
1 answer:
jenyasd209 [6]1 year ago
8 0

Aqueous Solution - The expected precipitate would consist of Cu(OH)2.

What is aqueous solution?

An aqueous solution is one in which water serves as the solvent. Chemical equations typically illustrate it by adding (aq) to the appropriate chemical formula. For instance, Na+(aq) + Cl would be used to represent a solution of table salt, as well as sodium chloride (NaCl), throughout water (aq). The word aqueous, which derives from the word aqua, means that it is dissolved in or related to water. Water is a common solvent in chemistry due to its superior solvent properties and natural abundance. Since water is frequently used as a solvent in experiments, unless the solvent is specified, the word "solution" refers to an aqueous solution. A solution wherein the solvent is a liquid but not water is referred to as a non-aqueous solution.

Because:

salt:    copper(II) hydroxide
Ksp:    1.8 × 10-19

To learn more about aqueous solution from the given link:
brainly.com/question/19587902
#SPJ4

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3 years ago
A 2.5% (by mass) solution concentration signifies that there is of solute in every 100 g of solution. 2. therefore, when 2.5% is
Stels [109]
Answer #1. A 2.5% (by mass) solution concentration signifies that there is 2.5 grams of solute in every 100 g of solution. 
To calculate 2.5% by mass solution, we divide the mass of the solute by the mass of the solution and then multiply by 100.

Answer #2. therefore, when 2.5% is expressed as a ratio of solute mass over solution mass, that mass ratio would be 2.5/100 or 2.5 grams of solute/100 grams of solution. 
This means that weighing out 2.5 grams of solute and then adding 97.5 grams of solvent would make a total of 100 gram solution:
     mass of solute / mass of solution = 2.5g solute / (2.5g solute + 97.5g solvent)
                                                          = 2.5g solute / 100g solution

Answer#3. a solution mass of 1 kg is 10 times greater than 100 g, thus 1kg of a 2.5% ki solution would contain 25 grams of ki.
Since 1000 grams is 1 kg, we multiply 10 to each mass so that 100 grams becomes 
1000grams:
     mass of solute / mass of solution = 2.5g*10 / [(2.5g*10) + (97.5g*10)]
                                                          = 25g solute/(25g solute + 975g solvent)
                                                          = 25g solute/1000g solution
                                                          = 25g solute/1kg solution
6 0
4 years ago
A gas mixture with a total pressure of 770 mmHg contains each of the following gases at the indicated partial pressures: 128 mmH
Alina [70]

Answer:

227 mmHg

Explanation:

Ptotal= PCO2 +PAr+PO2+PHe

PHe= Ptotal-PCO2 -PAr-PO2

PHe= (770 mmHg)-(128 mmHg)-(232 mmHg)-(183 mmHg)

PHe=227 mmHg

4 0
4 years ago
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