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2 years ago

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This reaction is first order with respect to reactant a and second order with respect to reactant b. if the concnetration of a i

s doubled and the concnetration of b is halved, th erate of the reaction would _______.

1 answer:

zaharov [31]2 years ago

3 0

Answer:

The rate of the reaction would be halved.

Explanation:

The reaction is first order with respect to reactant A and second order with respect to reactant B. The rate equation is [A][B]^2

If the concentration of A is doubled and the concentration of B is halved, rate = 2 × (1/2)^2 = 2 × 1/4 = 1/2.

The rate would be halved.

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He predicted an element with an atomic weight between 65 (zinc) and 75 (arsenic) with a valence similar to aluminum that he name

skad [1K]

Answer:

Scandium

Explanation:

Mendeleev played an important role in the development of the modern periodic table. His periodic table was filled with gaps. He said that these gaps were elements that were yet to be discovered. He rightly predicted many elements which have now been discovered and fitted in their proper places in the periodic table.

He used the prefix ''eka'' to refer to elements whose properties were alike but were yet to be discovered at that time.

The compound named ekaboron which he predicted to have an atomic weight between 65 (zinc) and 75 (arsenic) with a valence similar to aluminum was later discovered in 1879 and properly named scandium.

3 0

3 years ago

elixir [45]

Answer:

True

Explanation:

4 0

3 years ago

Consider the reaction below. If you start with 4.00 moles of C3H8 (propane) and 4.00 moles of O2 , how many moles of propane wou

fgiga [73]

Answer:

0.800 mol

Explanation:

We have the amounts of two reactants, so this is a limiting reactant problem.

We know that we will need a balanced equation with moles of the compounds involved.

Step 1. <em>Gather all the information</em> in one place.

C₃H₈ + 5O₂ ⟶ 3CO₂ + 4H₂O

n/mol: 4.00 4.00

===============

Step 2. Identify the <em>limiting reactant </em>

Calculate the <em>moles of CO₂</em> we can obtain from each reactant.

<em>From C₃H₈:</em>

The molar ratio of CO₂: C₃H₈ is 3:1

Moles of CO₂ = 4.00 × 3/1

Moles of CO₂ = 12.0 mol CO₂

<em>From O₂</em>:

The molar ratio of CO₂: O₂ is 3:5.

Moles of CO₂ = 4.00 × ⅗

Moles of CO₂ = 2.40 mol CO₂

O₂ is the limiting reactant because it gives the smaller amount of CO₂.

==============

Step 3. Calculate the <em>moles of C₃H₈ consumed</em>.

The molar ratio of C₃H₈:O₂ is 1:5.

Moles of C₃H₈ = 4.00 × ⅕

Moles of C₃H₈ = 0.800 mol C₃H₈

7 0

3 years ago

How does intertia affect gymnastics

Olegator [25]

Inertia is resistance to changes in motion. Which means if you are at rest it takes an external force to get you moving. And once you are moving it takes an external force to change the direction of that motion.

<span>For a person doing gymnastics the point that is subject to the above statement is her center of mass (roughly her belly button) . </span>

<span>So for example, once you launch into the air, gravity is the only significant force on you. It keeps you from traveling out into space by pulling you down and the trajectory of your belly button is a parabola. Now there is nothing you can do with your muscles (internal forces) to change that trajectory, even though you can do twists & turns about the center of mass. The height and range of the parabolic trajectory is determined by the angle & speed at which you initially launch yourself.
_____________________________________________________________
</span><span>inertia is one of newtons laws of motion so an object in motion tends to remain in motion until another force acts upon it that is what newton said when you are doing a back hand spring it is easier to keep going then to stop
</span><span>_____________________________________________________________

Hope this helps!!! :D
I love gymnastics!!!!</span>

6 0

2 years ago

My professor gave me two questions to solve using the Van Der Waals Equation. She told us to solve for P and the second one we h

Fed [463]

Answer:

P=atm

$b=\frac{L}{mol}$

Explanation:

The problem give you the Van Der Waals equation:

$(P+\frac{n^{2}a}{V^{2}})(V-nb)=nRT$

First we are going to solve for P:

$(P+\frac{n^{2}a}{V^{2}})=\frac{nRT}{(V-nb)}$

$P=\frac{nRT}{(V-nb)}-\frac{n^{2}a}{v^{2}}$

Then you should know all the units of each term of the equation, that is:

$P=atm$

$n=mol$

$R=\frac{L.atm}{mol.K}$

$a=atm\frac{L^{2}}{mol^{2}}$

$b=\frac{L}{mol}$

$T=K$

$V=L$

where atm=atmosphere, L=litters, K=kelvin

Now, you should replace the units in the equation for each value:

$P=\frac{(mol)(\frac{L.atm}{mol.K})(K)}{L-(mol)(\frac{L}{mol})}-\frac{(mol^{2})(\frac{atm.L^{2}}{mol^{2}})}{L^{2}}$

Then you should multiply and eliminate the same units which they are dividing each other (Please see the photo below), so you have:

$P=\frac{L.atm}{L-L}-atm$

Then operate the fraction subtraction:

P= $P=\frac{L.atm-L.atm}{L}$

$P=\frac{L.atm}{L}$

And finally you can find the answer:

P=atm

Now solving for b:

$(P+\frac{n^{2}a}{V^{2}})(V-nb)=nRT$

$(V-nb)=\frac{nRT}{(P+\frac{n^{2}a}{V^{2}})}$

$nb=V-\frac{nRT}{(P+\frac{n^{2}a}{V^{2}})}$

$b=\frac{V-\frac{nRT}{(P+\frac{n^{2}a}{V^{2}})}}{n}$

Replacing units:

$b=\frac{L-\frac{(mol).(\frac{L.atm}{mol.K}).K}{(atm+\frac{mol^{2}.\frac{atm.L^{2}}{mol^{2}}}{L^{2}})}}{mol}$

Multiplying and dividing units,(please see the second photo below), we have:

$b=\frac{L-\frac{L.atm}{atm}}{mol}$

$b=\frac{L-L}{mol}$

$b=\frac{L}{mol}$

7 0

3 years ago