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dybincka [34]
3 years ago
13

This reaction is first order with respect to reactant a and second order with respect to reactant b. if the concnetration of a i

s doubled and the concnetration of b is halved, th erate of the reaction would _______.
Chemistry
1 answer:
zaharov [31]3 years ago
3 0

Answer:

The rate of the reaction would be halved.

Explanation:

The reaction is first order with respect to reactant A and second order with respect to reactant B. The rate equation is [A][B]^2

If the concentration of A is doubled and the concentration of B is halved, rate = 2 × (1/2)^2 = 2 × 1/4 = 1/2.

The rate would be halved.

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The value of Kp for the reaction NO(g) 1 1 2 O2(g) 4 NO2(g) is 1.5 3 106 at 25°C. At equilibrium, what is the ratio of PNO2 to P
expeople1 [14]

Answer : The ratio of p_{NO_2} to p_{NO} is, 6.87\times 10^5

Solution :  Given,

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The given equilibrium reaction is,

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The expression of K_p will be,

K_p=\frac{(p_{NO_2})}{(p_{NO})\times (p_{O_2})^{\frac{1}{2}}}

Now put all the given values in this expression, we get:

1.5\times 10^6=\frac{(p_{NO_2})}{(p_{NO})\times (0.21)^{\frac{1}{2}}}

\frac{(p_{NO_2})}{(p_{NO})}=(1.5\times 10^6)\times (0.21)^{\frac{1}{2}}

\frac{(p_{NO_2})}{(p_{NO})}=6.87\times 10^5

Therefore, the ratio of p_{NO_2} to p_{NO} is, 6.87\times 10^5

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Hope this helps!
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